Answer:
x=41
Step-by-step explanation:
Answer:
TRUE
Step-by-step explanation:
tanθ = 1/cotθ
cotθ = 0 when θ = ±(1/2)π, ±(3/2)π, … ±[(2n+1)/2]π.
∴ tanθ is undefined when θ = ±[(2n+1)/2]π.
secθ = 1/cosθ
cosθ = 0 when θ = ±(1/2)π, ±(3/2)π, , …, ±[(2n+1)/2]π.
∴ secθ is undefined when θ = ±[(2n+1)/2]π.
The tangent and secant functions are undefined for the same values of θ.
Answer:
D
Step-by-step explanation:
=
= 
and
=
=
= 
Hence expression D is equivalent
Answer:
sin (2A+2B) = 0
Step-by-step explanation:
Given that,
cosec A= -2 and sec B= -2, A and B lie in the same quadrant.
We need to find the value of sin (2A+2B).

And

To find the value of sin (2A+2B) as follows :
sin [2(-30)+2(120)] = sin (-60+240)
=sin (180)
= 0
So, the value of sin (2A+2B) is qual to 0.
Answer:
can you explane a bit better
Step-by-step explanation: