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fenix001 [56]
3 years ago
10

State, and briefly explain, whether the width of a confidence interval for one population proportion would decrease, increase, o

r remain the same as a result of each of the following changes (holding all other values constant): 7. a. Decrease the sample (0.5 point) b. Increase the value of the sample mean (0.5 point) c. Reduce the value of a (alpha) (0.5 point)
Mathematics
1 answer:
Semenov [28]3 years ago
6 0

Answer:

<h3>The option b) is correct</h3><h3>The width of a confidence interval for one population proportion would decrease, increase, or remain the same as a result is <u>Increase the value of the sample mean (0.5 point) </u></h3>

Step-by-step explanation:

Given that the width of a confidence interval for one population proportion would decrease, increase, or remains the same.

<h3>To find the result for the given data :</h3>

By definition we have that "the width for the confidence interval decreases as the sample size increases". The width of the confidence interval increases as same as the standard deviation also increases. The width increases as the confidence level increases between (0.5 towards 0.99999 - stronger).

The width of a confidence interval is affected by 3 measures. they are the value of the multiplier t* , the standard deviation s of the original data, and the sample size of n .

<h3>Therefore the width of a confidence interval for one population proportion would decrease, increase, or remain the same as a result is <u>Increase the value of the sample mean (0.5 point) </u></h3><h3>Therefore the option b) is correct</h3>
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A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious
Dominik [7]

Answer:

Part1) z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

p_v =2*P(Z>2.191)=0.0284

Readjustment is needed

Part 2)  z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

p_v =2*P(Z

No readjustment is needed

Step-by-step explanation:

Data given and notation

Part 1    

\bar X=16.32 represent the sample mean    

\sigma=0.8 represent the population standard deviation    

n=30 sample size    

\mu_o =16 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed test.    

What are H0 and Ha for this study?    

Null hypothesis:  \mu =16    

Alternative hypothesis :\mu \neq 16    

Compute the test statistic  

The statistic for this case is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z>2.191)=0.0284

Using the value of \alpha =0.05 we see that pv and we have enough evidence to reject the null hypothesis.

Readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)    

Part 2

\bar X=15.82 represent the sample mean    

We can replace in formula (1) the info given like this:    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z

Using the value of \alpha =0.05 we see that pv>\alpha and we have enough evidence to FAIL to reject the null hypothesis.

No readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)  

What action would you recommend ?

Review the procedure.

Do you reach the same conclusion ?

No we got different conclusions

5 0
4 years ago
What is the length of AB?
DENIUS [597]

Answer:

C=10

Step-by-step explanation:

A^2 + B^2 = C^2

A=6

B=8

C=?

A^2=36

B^2=64

C^2=100

7 0
3 years ago
Karlen started painting the walls at 10:45 am, and he said that he could complete the job at 5:25 pm. His father said that five-
Vika [28.1K]

Answer:

idk

Step-by-step explanation:

im a dumby

5 0
4 years ago
Round your answer to the nearest tenth if necessary. Use 3.14 for .
harina [27]

Answer:

\boxed{\rm \: Volume_{(Drum)} = 5024 \: in {}^{3} }

Step-by-step explanation:

Given :

  • Diameter of a drum = 20 inches
  • Deep ( height ) of the drum = 16 inches
  • π = 3.14

To Find:

The volume of the drum.

Solution:

We all know that drum is cylindrical.So we'll use the formulae of the volume of cylinder,to find its volume.

\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}

Where,

  • r = radius
  • h = height (deep)
  • π = 3.14

The value of radius ain't given,but the diameter is given.We can use the formulae of radius.

\rm \: Radius = D/2

  • D = diameter

Substitute the value of diameter:

\rm \: Radius =  \cfrac{20}{2}  = 10

Hence,the radius is 10.

So we could now use the formulae of the volume of cylinder:

\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h

  • π = 3.14
  • r =10 in
  • h = 16 in

<em>[Firstly bring the answer in terms of π then plug π = 3.14 and then simplify.]</em>

\rm \: Volume_{(Drum)} = \pi(10) {}^{2} (16)

\rm \: Volume_{(Drum)} =\pi100(16)

\rm \: Volume_{(Drum)} = 1600\pi

\rm \: Volume_{(Drum)} = 1600 \times 3.14

\boxed{\rm \: Volume_{(Cylinder)} = 5024 \: in {}^{3}}

<u>Hence, we can conclude that:</u>

The volume of this drum is 5024 in^3.

8 0
2 years ago
I'm supposed to find the error in this problem
igor_vitrenko [27]

Answer:

The height is 12 cm instead of 13 cm

Step-by-step explanation:

use 12 Cm to take out answer

6 0
3 years ago
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