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Assoli18 [71]
3 years ago
11

Which quality allows programmers to modify a program as and when required

Computers and Technology
2 answers:
seropon [69]3 years ago
8 0

Answer:

d. flexibility

Explanation:

Flexibility in its generic term is a measure of how bendable a thing is. It connotes how easily changes can be made to an object.

In the software context, flexibility is the adaptability of a program to future modifications. It is a quality of a program, software or application that allows programmers to modify it when required.

Flexibility allows to modify codes without having to re-write them. If software applications were not flexible, making new and updated releases of them would be a herculean task.

lana66690 [7]3 years ago
5 0
I think Flexibility. Because when you are flexible you are able to manage things at anytime.
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Return the "centered" average of an array of ints, which we'll say is the mean average of the values, except ignoring the larges
denpristay [2]

Answer:

The code to this question can be defined as follows:

public double centeredAverage(ArrayList<Integer> nums) //defining a method centeredAverage that accepts an array nums

{

   if ((nums == null) || (nums.size() < 3))//define if block for check simple case value

   {

       return 0.0;//return float value

   }

   double sum = 0; //defining a double variable sum

   int smallest = nums.get(0);//defining integer variable and assign value

   int largest = nums.get(0);//defining integer variable and assign value

   for (int i = 0; i < nums.size(); i++) //defining for loop for stor ith value

   {

       int value = nums.get(i);//defining integer value variable to hold nums value

       sum = sum + value;//use sum variable for add value

       if (value < smallest)//defining if block to check value less then smallest

           smallest = value;//hold value in smallest variable  

       else if (value > largest)//defining else if block that checks value greater them largest value

           largest = value; //hold value in largest variable

   }

   sum = sum - largest - smallest;  // use sum to decrease the sum largest & smallest value

   return (sum / (nums.size() - 2)); //use return keyword for return average value

}

Explanation:

In the question, data is missing, that's why the full question is defined in the attached file please find it.

In the given code a method "centeredAverage" is used that accepts an array in its parameter and inside the method, if block is used that checks the cash value if it is true, it will return a float value.

In the next step, two integers and one double variable is defined, that use the conditional statement for check hold value in its variable and at the last use return keyword for return average value.

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