Hey there
It may be the lomy soil
Besides the sandy soil ,clay soil can not be used for growing plants or farming
Hope u derived something from this
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Aluminum can be oxidized by
and 
<h3>What is oxidizing?</h3>
Some of the metal corrodes (or oxidizes) and forms the corresponding metal oxide on the surface as a result of a chemical reaction between the metal surface and the oxygen in the air. The corrosion products that occur in some metals, like steel, are highly apparent and loose.
According to reactivity series (The array of metals in the descending order of their reactivities is referred to as the metals' reactivity series. It is sometimes referred to as the metals in the activity series.)
Lithium and calcium ions are more reactive than aluminum ion and they are less electronegative.
Since silver and tin are more electronegative than aluminum so, they cannot oxidize aluminum.
∴
and
ions can oxidize aluminum.
Learn more about electronegativity here brainly.com/question/16446391
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Answer:
numerical values such as measurements, cost, and weight;
Explanation:
The hair colors of players on a football team
the color of cars in a parking lot
the letter grades of students in a classroom
the shape of candies in a variety pack
(Answer) 0.166 moles of copper (I) nitride are needed.
Mass of copper (I) oxide = 35.7 g
Moles of copper (I) oxide formed by the reaction = (Mass / molar mass)
= ( 35.7 g / 143.09 g/mol ) = 0.25 moles
According to the balanced chemical equation,
mole ratio of copper (I) nitride and copper (I) oxide = 2: 3
Therefore, moles of copper (I) nitride needed to form 0.25 moles of copper (I) oxide = (2/3 x 0.25) moles = 0.166 moles.
Thus, 0.166 moles of copper (I) nitride are needed to form 0.25 moles of copper (I) oxide.
Hello
The balance chemical reaction is 2Al + 6HCl -à 2AlCl3 + 3H2 Assuming excess amount of HCl because it is not given Mole Al reacted = 13.5 g ( 1 mole/ 27 g) = 0.5 mole Al
Mole H2 = 0.5 mol Al ( 3 mole H2 / 2 mole Al) = 0.75 mole H2
since at STP then 1 mole gas occupies 22.414 L volume H2 = 0.75 mole (22.414 L / mol) = 16.8105 L H2
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