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3 years ago

15

Balance chemical equation Fe3O4 = Fe + CO2

1 answer:

m_a_m_a [10]3 years ago

5 0

equation Fe3O4=Fe+CO2 is an impossible reaction

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Ano ang kaganapan na nangyari at nasabing nagsimula ang holy ramon empire

Ksenya-84 [330]

Answer:

plzz give the question in English

5 0

3 years ago

Tris is a molecule that can be used to prepare buffers for biochemical experiments. It exists in two forms: Tris (a base) and Tr

ale4655 [162]

Solution :

For the reaction :

$\text{TrisH}^+ + H_2O \rightarrow \text{Trish}^- + H_3O^+$

we have

$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$

$=\frac{x^2}{0.02 -x}$

$=8.32 \times 10^{-9}$

Clearing $x$ , we have $x = 1.29 \times 10^{-5} \text{ moles of acid}$

So to reach $\text{pH} = 7.8 (\text{pOH}= 14-7.8=6.2)$ , one must have the $\text{OH}^-$ concentration of the :

$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$

So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.

$\text {n NaOH}=1.29 \times 10^{-5}+6.31 \times 10^{-7}$

$= 1.35 \times 10^{-5} \text{ moles}$

Volume NaOH $= 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \text{ mL}}{1 \text{ mol}} = 0.0135 \text{ mL}$

Tris mass $H^+ = 0.02 \text{ mol} \times 157.6 \text{ g/mol}=3.152 \text{ g}$

Now to prepare the said solution we must mix:

$3.152 \text{ g Tris H} + 0.0135 \text{ mL NaOH} \ 1 M$ gauge to 1000 mL with water.

3 0

2 years ago

H2SO4 +HI → __ H2S+12 +H2O balance the equation

Citrus2011 [14]

Answer:

H2SO4 + 8HI → H2S + 4I2 + 4H2O

3 0

2 years ago

A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature

Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

$v_0=500$
$\alpha =1.12\times 10^{-4}$
$\Delta \epsilon = 25$

Now,

Increase in volume will be:

⇒ $\Delta V = \alpha\times v_0\times \Delta \epsilon$

By putting the given values, we get

$=1.12\times 10^{-4}\times 500\times 25$

$=1.12\times 10^{-4}\times 12500$

$=1.4 \ mL$

8 0

3 years ago

What is the wavelength of light with 2.89 x 10-19 J of energy? (The speed of

Alika [10]

Let's see

$\\ \rm\rightarrowtail E=hv$

$\\ \rm\rightarrowtail E=\dfrac{hc}{\lambda}$

lambda is wavelength
h is Planck constant
c is velocity of sound in air
E in energy

$\\ \rm\rightarrowtail \lambda=\dfrac{hc}{E}$

$\\ \rm\rightarrowtail \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{2.89\times 10^{-19}}$

$\\ \rm\rightarrowtail \lambda=6.878\times 10^{-7}m$

$\\ \rm\rightarrowtail \lambda=68.8\mu m$

3 0

1 year ago