Answer:
9.9 ml of 0.200M NH₄OH(aq)
Explanation:
3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)
?ml of 0.200M NH₄OH(aq) reacts completely with 12ml of 0.550M FeCl₃(aq)
1 x Molarity NH₄OH x Volume Am-OH Solution(L) = 2 x Molarity FeCl₃ x Volume FeCl₃ Solution
1(0.200M)(Vol Am-OH Soln) = 3(0.550M)(0.012L)
=> Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liter = 9.9 milliliters
Answer:
Rise surface fall surface rise
Explanation:
Hope this helps!
Answer:
2 NaI ---> 2 Na + I₂
Explanation:
The only way the reactant NaI can decompose is by separating into 2 atoms, Na and I. However, you must take into account that iodine (I) exists as a diatomic molecule.
An equation is balanced when there is an equal amount of each element on both sides of the reaction. These amounts can be modified by adding coefficients in from of the molecules/atoms.
The unbalanced equation:
NaI -----> Na + I₂
<u>Reactants</u>: 1 sodium, 1 iodine
<u>Products</u>: 1 sodium, 2 iodine
The balanced equation:
2 NaI ---> 2 Na + I₂
<u>Reactants</u>: 2 sodium, 2 iodine
<u>Products</u>: 2 sodium, 2 iodine
