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Luda [366]
3 years ago
13

What is the vertical asymptotes of the function f(x)=x-2/x*2-3x-4

Mathematics
1 answer:
frozen [14]3 years ago
4 0

Answer:

<h2>x = -1 and x = 4</h2>

Step-by-step explanation:

f(x)=\dfrac{x-2}{x^2-3x-4}\\\\\text{DOMAIN}:\\\\x^2-3x-4\neq0\\\\x^2-4x+x-4\neq0\\\\x(x-4)+1(x-4)\neq0\\\\(x-4)(x+1)\neq0\iff x-4\neq0\ \wedge\ x+1\neq0\\\\x\neq4\ \wedge\ x\neq-1\\\\\text{Therefore the vertical asymptotes are:}\\\\x=-1\ and\ x=4.

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Answer:

7/6

Step-by-step explanation:

In order to find slope when you have two ordered pairs, you use this equation: (y2-y1)/(x2-x1)

In this case, when you plug them in, you get (49-7)/(42-6), which is 42/36, which is 7/6.

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3 years ago
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Scorpion4ik [409]
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3 years ago
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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

8 0
3 years ago
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Write the standard form of the line that passes through the given points. include your work in your final answer. (-1, -3) and (
yan [13]

The standard form of a line passing through the points (-1, -3) and (2, 1) is <u>4x - 3y = 5</u>.

The slope of the given line, m = (1 - (-3))/(2 - (-1)) = (1 + 3)/(2 + 1) = 4/3.

Computed using the formula for the slope of a line, m = (y₂ - y₁)/(x₂ - x₁), when a line passes through the points (x₁, y₁) and (x₂, y₂).

The point intercept form of a line is <u>y - y₁ = m(x - x₁)</u> when the line passes through the point (x₁, y₁) and has the slope m.

Thus, the given line in the point intercept form can be written as:

y - 1 = (4/3)(x - 2).

The standard form of a line is ax + by = c.

To convert the point intercept form to the standard form, we do as follows:

y - 1 = (4/3)(x - 2),

or, 3(y - 1) = 3(4/3)(x - 2) {Multiplying both sides by 3},

or, 3y - 3 = 4x - 8 {Simplifying},

or, 8 - 3 = 4x - 3y {Rearranging},

or, 4x - 3y = 5 {Rearranging and simplifying}.

Thus, the standard form of a line passing through the points (-1, -3) and (2, 1) is <u>4x - 3y = 5</u>.

Learn more about equations of straight lines at

brainly.com/question/13763238

#SPJ4

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2 years ago
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