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3 years ago

What is the vertical asymptotes of the function f(x)=x-2/x*2-3x-4

Mathematics

1 answer:

frozen [14]3 years ago

4 0

Answer:

Step-by-step explanation:

$f(x)=\dfrac{x-2}{x^2-3x-4}\\\\\text{DOMAIN}:\\\\x^2-3x-4\neq0\\\\x^2-4x+x-4\neq0\\\\x(x-4)+1(x-4)\neq0\\\\(x-4)(x+1)\neq0\iff x-4\neq0\ \wedge\ x+1\neq0\\\\x\neq4\ \wedge\ x\neq-1\\\\\text{Therefore the vertical asymptotes are:}\\\\x=-1\ and\ x=4.$

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r-ruslan [8.4K]

Answer:

c) 0.932

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Step-by-step explanation:

Explanation:-

Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.

size of the sample 'n' = 35

mean of the sample x⁻= 1.01lbs

standard deviation of the sample 'S' = 0.18lbs

<u>The 99% confidence intervals are given by</u>

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )$

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( 1.01 - 0.06183 , 1.01+0.06183)

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<u>Final answer</u>:-

<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>

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3 years ago