What is the vertical asymptotes of the function f(x)=x-2/x*2-3x-4
1 answer:
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Answer:
Step-by-step explanation:
slope-intercept form: y = mx + b
y = (x , y)
x = (x , y)
m = slope = 1/2
b = y-intercept = 89
Plug in the corresponding numbers & variables to the corresponding variables:
y = (1/2)x + 89
is your answer.
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F(x)=![\sqrt[3]{x+2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%2B2%7D%20)
to solve for the inverse of a function you do 4 steps:
1. subsitute f(x) with y
2. switch y and x places
3. solve for y
4. subsitute y with f⁻¹(x)
so we have
f(x)=
subsitute f(x) with y
y=
switch x and y
x=![\sqrt[3]{y+2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7By%2B2%7D%20)
solve for y
x=
cube both sides
=y+2
subtract 2 from both sides
=y
subsitute y with f⁻¹(x)
f⁻¹(x)=
the answer is f⁻¹(x)=
to solve for the inverse of a function you do 4 steps:
1. subsitute f(x) with y
2. switch y and x places
3. solve for y
4. subsitute y with f⁻¹(x)
so we have
f(x)=
subsitute f(x) with y
y=
switch x and y
x=
solve for y
x=
cube both sides
subtract 2 from both sides
subsitute y with f⁻¹(x)
f⁻¹(x)=
the answer is f⁻¹(x)=