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3 years ago

13

What is the vertical asymptotes of the function f(x)=x-2/x*2-3x-4

1 answer:

frozen [14]3 years ago

4 0

Answer:

<h2>x = -1 and x = 4</h2>

Step-by-step explanation:

$f(x)=\dfrac{x-2}{x^2-3x-4}\\\\\text{DOMAIN}:\\\\x^2-3x-4\neq0\\\\x^2-4x+x-4\neq0\\\\x(x-4)+1(x-4)\neq0\\\\(x-4)(x+1)\neq0\iff x-4\neq0\ \wedge\ x+1\neq0\\\\x\neq4\ \wedge\ x\neq-1\\\\\text{Therefore the vertical asymptotes are:}\\\\x=-1\ and\ x=4.$

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Answer:

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Step-by-step explanation:

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3 years ago

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Colt1911 [192]

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3 years ago

Read 2 more answers

Help me plzzzzzzzzz<br> solve for x

Svet_ta [14]

Answer:

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---------------------

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$4x=32$

$x=\frac{32}{4}$

$x=8$

<u>---------------------</u>

hope it helps...

have a great day!!

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3 years ago