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Ivahew [28]
3 years ago
6

A football field is 1000 yards long.Each if the two end zones adds an extra 10 yards . The field is 160 feet wide . What is the

area of the whole field ?
Mathematics
2 answers:
Kobotan [32]3 years ago
7 0

Answer:

The area of the whole field is 54400yd^2

Step-by-step explanation:

says that I add 10 yards in each zone, that means that 10 yards is added twice at 1000 yards

1000yd + 2*10yd = 1020yd

we have to know that one yard equals 3 feet

so to have the length in feet we only multiply it by 3

1020 * 3 = 3060ft

Now that we know the length and width of the court, we can calculate the area by multiplying them

a = b * h

a = 3060ft * 160ft

a = 489600 ft^2

the result is in square feet

if we want it in square yards we just have to divide 2 times by 3

489600/(3*3) = 54400yd^2

drek231 [11]3 years ago
6 0
First, you just add 1000 yards to two 10 yards, I’m pretty sure. So then you get 1020. Then you multiply 1020 by 160 feet to get an area of 163,200 square feet.
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Question:

Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park.There is a point at (−6, 3) labeled Dog 1. There is a point at (−6, −3) labeled Dog 2.

Which statement best describes the relationship between the positions of the two players?

A.Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

B.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

C.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

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Answer:

Option B: Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

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