Simplify fraction 4/28 and 24/80

The number 64 has the property that it is divisible by its units digit. How many whole numbers between 10 and 50 have this prope

sineoko [7]

Answer:

$\large \boxed{17}$

Step-by-step explanation:

Let's call the numbers "tu", where t is the tens digit and u is the units digit.

We can solve this by the "brute force" method — examining each number to see if it satisfies the conditions.

$\begin{array}{cccl}\mathbf{u}&\mathbf{tu}& \textbf{Divisible by u} & \\0 &20, 30, 40 & 0 & \text{Division by zero is impossible}\\1 & 11, 21, 31, 41 & 4& \text{All numbers are divisible by one}\\2 & 12, 22, 32, 42 & 4 & \text{All even numbers are divisible by two}\\3 & 13, 23, 33, 43 & 1 &\text{Only 33 is divisible by three}\\4 & 14, 24, 34, 44 & 2 & \text{Only 24 and 44 are divisible by four}\\5 & 15, 25, 35, 45 & 4 & \text{Numbers ending in 5 are divisible by five}\\\end{array}$

$\begin{array}{cccl}6 & 16, 26, 36, 46 & 1 & \text{Only 36 is divisible by six}\\7 & 17, 27, 37, 47 & 0 & \text{None of the numbers is divisible by seven}\\8 & 18, 28, 38, 48 & 1 & \text{Only 48 is divisible by eight}\\9 & 19, 29, 39, 49 & 0 & \text{None of the numbers is divisible by nine}\\& \textbf{TOTAL =} &\mathbf{17}& \\\end{array}\\\text{$\large \boxed{\mathbf{17}}$ numbers between 10 and 50 are divisible by their units digit}$

5 0

3 years ago

Please provide the answer?

Brums [2.3K]

Using the given table:

a) the average rate of change is 32.5 jobs/year.

b) the average rate of change is 12.5 jobs/year.

<h3>How to find the average rate of change?</h3>

For a function f(x), the average rate of change on an interval [a, b] is:

$\frac{f(b) - f(a)}{b - a}$

a) The average rate of change between 1997 and 1999 is:

$A = \frac{695 - 630}{1999 - 1997} = 32.5$

So the average rate of change is 32.5 jobs/year.

b) Now the interval is 1999 to 2001.

The rate this time is:

$A ' = \frac{720 - 695}{2001 - 1999} = 12.5$

So the average rate of change is 12.5 jobs/year.

If you want to learn more about average rates of change:

brainly.com/question/8728504

#SPJ1

3 0

2 years ago

Type the correct answer in each box

Luba_88 [7]

Answer:

We know that the equation of the circle in standard form is equal to (x-h)² + (y-k)² = r² where (h,k) is the center of the circle and r is the radius of the circle.

We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :

1 - We first group terms with the same variable :

(x²+8x) + (y²+22y) + 37 = 0

2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)

(x²+8x) + (y²+22y) = - 37

3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process "completing the square".

x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²

y²+22y = (y²+22y+11²)-11² = (y+11)²-11²

4 - We plug the new values inside our equation :

(x+4)² - 4² + (y+22)² - 11² = -37

(x+4)² + (y+22)² = -37+4²+11²

(x+4)²+(y+22)² = 100

5 - We re-write in standard form :

(x-(-4)²)² + (y - (-22))² = 10²

And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)

5 0

3 years ago

A triangle has an area of 54 square inches the height of the triangle is 12 inches what is the length of the base of the triangl

prohojiy [21]

Answer:

The base of the triangle = 9inches

Step-by-step explanation:

Explanation:-

The area of the triangle = $\frac{1}{2} bh$ square units

Given area of the triangle(A) = 54 square inches

Given the height of the triangle (h) = 12 inches

now equating $\frac{1}{2} b h = 54$

$\frac{1}{2} b (12) = 54$

now simplification, we get

6 b = 54

Dividing '6' on both sides, we get

b = 9

The base of the triangle = 9 inches

Conclusion:-

The base of the triangle = 9 inches

6 0

3 years ago

A pizza restaurant gave a 20% discount on the supreme pizza which cost $16. what was the sale price?

Inga [223]

Answer:

you saved $3.20

Step-by-step explanation:

16 x 20/100

16 x 0.2

= 3.20

so 16-3.20= 12.80

final price is 12.80

6 0

2 years ago