(3 x 10^10 Hg) x (1 mole Hg/6.022 x 10^23 Hg) x (200.59g / 1 mole Hg) =
99.928 x 10^-13
10^-9 g Hg x (1 mole Hg / 200.59 g Hg) x (6.022 x 10^23 Hg / 1 mole Hg) =
0.031 x 10^14 Hg = 3.1 x 10^12 Hg
I.) 10^-11 g Hg
II.) 3.1 x 10^12 Hg
Answer:
5.6
Explanation:
Because of the gravity of the earth
Answer:
The questions are incomplete
Explanation:
(b) This question is incomplete. However to calculate the number of moles of CuSO₄ present in the impure sample. The formula below can be used;
number of moles = mass of CuSO₄ present in the impure sample ÷ molar mass of CuSO₄
(c) This question is also incomplete. However, to calculate the mass percentage of CuSO₄ present in the impure sample of CuSO₄, the formula below can be used.
Mass percentage of CuSO₄ =
mass of CuSO₄ present in the impure sample/mass of impure CuSO₄ × 100
Thus, the mass of the impure sample must be measured also since the actual mass of the CuSO₄ present in the impure sample must have been measured before calculating the number of moles.
Answer:
it is the one below that. NO, because it debt net the octet rule
