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Oduvanchick [21]
3 years ago
8

1325 mg to kg convert

Chemistry
1 answer:
Elis [28]3 years ago
3 0

Answer: 0.001325

Explanation: Hope that this helps :)

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Calculate the freezing point of a solution containing 15 grams of kcl and 1650.0 grams of water. the molal-freezing-point-depres
Soloha48 [4]
Answer is: freezing point is -0,226°C.
Answer is: the molal concentration of glucose in this solution is 1,478 m.
m(KCl) = 15 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 15 g ÷ 74,55 g/mol.
n(KCl) = 0,2 mol
m(H₂O) = 1650 g ÷ 1000 g/kg = 1,65 kg.
b = n(KCl) ÷ m(H₂O).
b = 0,2 mol ÷ 1,65 kg = 0,122 m.
Kf(water) = 1,86°C/m.
ΔT = Kf(water) · b(solution).
ΔT = 1,86°C/m · 0,122 m.
ΔT = 0,226°C.
4 0
3 years ago
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Why don't we have a lunar eclipse every month?<br> PLEASE HURRY
cupoosta [38]

Answer:

Beacause  it does  just in a different place

Explanation:

7 0
2 years ago
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Name one Importance of solar power
spayn [35]
Because the sun is a sustainable source of energy that can be used to power homes and businesses globally. 

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An unknown rectangular substance measures 3.60cm high, 4.21cm long, and 1.17cm wide. If the mass is 21.3g what is this substance
tino4ka555 [31]

The rectangular substance measures 3.60cm high, 4.21cm long, and 1.17cm wide. If the mass is 21.3g  substances density will be 1.20 centimeter cube.

<h3>What is density?</h3>

The density of any substance is the ratio of the mass of substance to the volume of the substance and the unit will be centimeter cube.

The volume of the substance will be 3.60cm high × 4.21cm long ×1.17cm wide = 17.7 milliliters.

                       density = mass of substance / volume of substance

Substituting the value in formula

                        Density = 21.3g /  17.7 milliliters.

                         Density =  1.20 centimeter cube.

Therefore,  rectangular substance measures 3.60cm high, 4.21cm long, and 1.17cm wide. If the mass is 21.3g  substances density will be 1.20 centimeter cube.

Learn more about density, here:

brainly.com/question/15164682

#SPJ1

4 0
2 years ago
When you apply 1000 joules of energy to 50 grams of water its temperature changes to 30 degrees . What was the initial temperatu
expeople1 [14]

Answer:

25.2°C

Explanation:

Given parameters:

Energy applied to the water  = 1000J

Mass of water  = 50g

Final temperature  = 30°C

Unknown:

Initial temperature  = ?

Solution:

To solve this problem, we use the expression below:

            H  = m c Ф

H is the energy absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

     1000  = 50 x 4.184 x (30  -  initial temperature )

     1000  = 209.2(30 - initial temperature)

      4.78  = 30 - initial temperature

      4.78  - 30  = - initial temperature

         Initial temperature  = 25.2°C

7 0
3 years ago
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