CH3COH(CH3)2; (CH3)3COH is the answer. Please let me know if this helps.
To convert 78.1 g of water at 0° C to Ice at -57.1°C; we can do it in steps;
1. Water at 0°C to ice at 0°C
The heat of fusion of ice is 334 J/g;
Heat = 78.1 × 334 = 26085.4 Joules
2. Ice at 0°C to -57.1°C
Specific heat of ice is 2.108 J/g
Heat = 78.1 × 2.108 J/g = 164.6348 Joules
Thus the total heat energy released will be; 26085.4 + 164.6348
= 26250.0348 J or 26.250 kJ
1. NaF, Na₂S, Na₃P, Na₂O
2. MgF₂, MgS, Mg₃P₂, MgO
3. AlF₃, Al₂S₃, AlP, Al₂O₃
<h3>Further explanation</h3>
Given
Ionic charge
Required
The formula of binary ionic compounds
Solution
Ionic compounds consisting of cations (ions +) and anions (ions -)
Ionic compounds usually consist of metal cations and non-metal anions
Metal: cation, positively charged.
Nonmetal: negatively charged
The anion cation's charge is crossed
The ionic compounds :
1. NaF, Na₂S, Na₃P, Na₂O
2. MgF₂, MgS, Mg₃P₂, MgO
3. AlF₃, Al₂S₃, AlP, Al₂O₃
That would be phosphorus. It’s electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^3
