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aivan3 [116]
4 years ago
10

Explain how electromagnetic waves are produced

Chemistry
2 answers:
mezya [45]4 years ago
6 0
Electromagnetic radiation<span>, is a form of energy emitted by moving charged particles. As it travels through space it behaves like a </span>wave<span>, and has an oscillating electric field component and an oscillating magnetic field. These </span>waves<span> oscillate perpendicularly to and in phase with one another.</span>
V125BC [204]4 years ago
3 0

The source of electromagnetic waves are charged particles that begin to oscillate when acted upon by a disturbance. These oscillating particles create an oscillating magnetic field. The oscillating magnetic field then creates an oscillating electric field, and an oscillating electric field in turn creates an oscillating magnetic field.

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Help me please
vredina [299]

Answer:

an atom is the smallest unit of matter or a substance.

Explanation:

the structure of the

atom consists of electrons, protons, neutrons) which makes up the nucleus is more than a hundred thousand times smaller than it's atom but makes up 99.9% of the mass of the atom.

the protons are the positively charged particles. The neutrons are the negatively charged particles. The electrons are the negatively charged particles.

the first energy level consists of two electrons. the second energy level consists of eight electrons. the 3 energy level consists of eighteen electrons. the 4 energy level consists of thirty two electrons.

8 0
3 years ago
What is the percent composition of NaHCO3?
Katarina [22]

Answer:- Na = 27.37%, H = 1.20%, C = 14.30% and O = 57.14%

Solution:- For the percentage composition of a compound, the atomic mass of each atoms times its subscript is divided by the molar mass of the compound and multiplied by 100.

The given compound is NaHCO_3.

mass of Na = 22.99 g

mass of H = 1.008 g

mass of C = 12.01 g

mass of O = 3(16) = 48 g

Molar mass of compound = 22.99 g + 1.008 g + 12.01 g + 48 g = 84.008 g

percentage of Na = (\frac{22.99}{84.008})100

= 27.37%

percentage of H = (\frac{1.008}{84.008})100

= 1.20%

percentage of C = (\frac{12.01}{84.008})100

= 14.30%

percentage of O = (\frac{48}{84.008})100

= 57.14%


5 0
3 years ago
A water-salt solution with the same salt concentration as in cells is called:
olga2289 [7]
The Answer Is Equal....<span>EQUAL</span>
5 0
3 years ago
A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
4 years ago
Is this statement true or false?
eimsori [14]
The answer is A. = True
4 0
4 years ago
Read 2 more answers
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