Answer: option D) energy was absorbed and entropy increased.
Explanation:
1) Given balanced equation:
2H₂O (l) + 571.6 kJ → 2 H₂ (g) + O₂(g).
2) Being the energy placed on the side of the reactants means that the energy is used (consumed or absorbed). This is an endothermic reaction.
So, the first part is that energy was absorbed.
3) As for the entropy, it is a measure of the disorder or radomness of the system.
Since, two molecules of liquid water were transformed into three molecules of gas, i.e. more molecules and more kinetic energy, therefore the new state has a greater degree of radomness, is more disordered, and you conclude that the entropy increased.
With that, you have shown that the right option is D) energy was absorbed and increased.
Answer:
C is the reaction intermediate.
Explanation:
A reaction intermediate is a molecular structure that is formed during the reaction but then is converted in the final products.
Usually, these reaction intermediates are unestable and, for that reason, the lifetime of these structures is low.
In the reaction, you can see in the first step C is produced, but also, in the second step reacts producing D. As is produced and, immediately consumed,
<h3>C is the reaction intermediate.</h3>
Answer:
1. An encounter with the barrier
2. The distance traveled by the washer.
Explanation:
Answer:
A) Alkaline Earth Metals
Explanation:
Area Marked A would be Alkali Metals
Area Marked B would be Alkaline Earth Metals
Area Marked C would be Transition Metals
Area marked H would be Halogens
Answer:
3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu
Explanation:
From the question given above,
Copper (II) nitrate reacts with aluminum to form aluminum nitrate and copper. This can be obtained represent as follow:
Cu(NO3)2 + Al —> Al(NO3)3 + Cu
Thus, we can balance the above equation as follow:
Cu(NO3)2 + Al —> Al(NO3)3 + Cu
There are 2 atoms of N on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cu(NO3)2 and 2 in front of Al(NO3)3 as shown below:
3Cu(NO3)2 + Al —> 2Al(NO3)3 + Cu
There are 3 atoms of Cu on the left side and 1 atom on the right side. It can be balance by putting 3 in front Cu as shown below:
3Cu(NO3)2 + Al —> 2Al(NO3)3 + 3Cu
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Al as shown below:
3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu
Thus, the equation is balanced.
