Answer:
The amount of positive charge in a barium nucleus is approximately 8.972 × 10⁻¹⁸ coulomb
Explanation:
The amount of positive charge there is in a barium nucleus is found as follows;
The atomic number of an element is equal to the number of proton present in the atom
The atomic number of barium = 56 = The number of protons in an atom of barium
The positive charge of a single proton is known as an elementary charge, e, given by the formula, e = F/N
Where;
F = Faraday's constant
N = The Avogadro's number
Therefore, e = 1.602 176 634 × 10⁻¹⁹ C
Which gives the positive charge, Q, of the protons of a barium nucleus as follows;
Q = Number of protons × e
Q = 1.602176634 × 10⁻¹⁹ × 56 ≈ 8.972 × 10⁻¹⁸ Coulomb per atom of barium.
The amount of positive charge in a barium nucleus ≈ 8.972 × 10⁻¹⁸ coulomb.
Answer: c. +4
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here manganese is having an oxidation state of +4 called as cation and oxygen forms an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged to give which written in simplest whole number ratios to give neutral