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muminat
3 years ago
8

In coulombs, how much positive charge is there IN a barium nucleus? On a barium ion?

Chemistry
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

The amount of positive charge in a barium nucleus is approximately 8.972 × 10⁻¹⁸ coulomb

Explanation:

The amount of positive charge there is in a barium nucleus is found as follows;

The atomic number of an element is equal to the number of proton present in the atom

The atomic number of barium = 56 = The number of protons in an atom of barium

The positive charge of a single proton is known as an elementary charge, e, given by the formula, e = F/N_A

Where;

F = Faraday's constant

N_A = The Avogadro's number

Therefore, e = 1.602 176 634 × 10⁻¹⁹ C

Which gives the positive charge, Q, of the protons of a barium nucleus as follows;

Q = Number of protons × e

Q = 1.602176634 × 10⁻¹⁹ × 56 ≈ 8.972 × 10⁻¹⁸ Coulomb  per atom of barium.

The amount of positive charge in a barium nucleus ≈ 8.972 × 10⁻¹⁸ coulomb.

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3 years ago
Please help i dont understand it
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Answer:-  solution boiling point = 102.23 degree C (102 degree C with three sig figs).

Solution:- When a non volatile solute is added to a solvent then boiling point increases. Elevation in boiling point is directly proportional to the molality of the solution.

The equation is:

\Delta T_b=i*k_b*m

where, \Delta T_b is the elevation in boiling point, i is the Van't hoff factor, k_b is the molal elevation constant and m is the molality.

Value of i is 1 as ethylene glycol is a covalent molecule that does not break to give ions. k_b for water is \frac{0.512^0C}{m} .

We can calculate the molality from the given grams of ethylene glycol and liters of water as molality is moles of solute per kg of solvent.

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2.50L(\frac{1kg}{1L})

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Let's plug in the values in the equation we have on the top for elevation in boiling point.

\Delta T_b=4.36m(\frac{0.512^0C}{m})

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(If we fix the three sig figs then it could be written as 102 degree C.)

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Normally, we would need a balanced chemical equation.

However, we can get by with a partial equation, as log as carbon atoms are balanced.

We know we will need an equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.  

M_r:    30.07          236.74

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m/g:    90.0

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n = 90.0 g C₂H₆  × (1 mol C₂H₆ /30.07 g C₂H₆)

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m = 709 g C₂Cl₆

The reaction produces 709 g C₂Cl₆.

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