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erastova [34]
3 years ago
12

Calculate the average speed of a complete round trip in which the outgoing 300 km is covered at 93 km/h , followed by a 1.0-h lu

nch break, and the return 300 km is covered at 56 km/h . Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
madreJ [45]3 years ago
3 0

Answer : 63 km/h

Explanation :

Outgoing distance = 300 km.

Outgoing speed = 93 km/h.

Break time = 1 h

Return distance = 300 km

Return speed = 56 km/h

Outgoing time  = outgoing distance / outgoing speed

Outgoing time   = 300 km / 93 km/h = 3.225806451612 h

Return time  = return distance / return speed

Return time = 300 km / 56 km/h = 5.357142867142 h

Total distance =. Outgoing distance + return distance travelled

Total distance  = 300 km + 300 km = 600 km

Total time = outgoing time + break time + return time

Total time = 3.225806451612 h + 1 h+ 5. 357142867142 h = 9.582949308754 h

Average speed = total distance / total time

Average speed = 600 km / 9.582949308754 h

Average speed = 62.61120462042 km/h = 63 km/h

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Answer:

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To know the time that took for Neil Armstrong's voice to reach the Earth via radio waves, the following equation can be used:

c = \frac{d}{t}  (1)

Where v is the speed of light, d is the distance and t is the time.

Notice that t can be isolated from equation 1.

t = \frac{d}{c}  (2)

The distance from the Earth to the Moon is 3.85x10^{8} m, therefore.

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The distance from the Earth to the Mars at its closest approach is 5.76x10^{10}m, therefore.

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