Answer:
0.022kg/s
Explanation:
We are given that
Mass of boiled egg=46 g=
Constant force=F=25.6 N/m
Initial displacement=
Final displacement=
Time=t=4.55 s
Damping force=
We have to find the magnitude of damping constant b.
We know that the displacement of the oscillator under damping motion is given by
For maximum displacement
Therefore ,
Substitute the values
Substitute the values
Hence,the magnitude of damping constant b=0.022kg/s
Answer:
F= 5.71 N
Explanation:
width of door= 0.91 m
door closer torque on door= 5.2 Nm
In order to hold the door in open position we need to exert an equal and opposite torque, to the door closer torque, on the door.
so wee need to exert 5.2 Nm torque on the door.
If we want to apply minimum force to exert the required torque we need to apply force perpendicularly on the door knob (end of door) so that to to greater moment arm.
T= r x F
T= r F sin∅
F= T/ (r * sin∅)
F= 5.2/ (0.91 * 1)
F= 5.71 N
Answer:
The number of photons per second that strike the given area is 2.668 x 10⁸ photons/second
Explanation:
Given;
intensity of the sunlight, I = 2.00 kJ·s−1·m^−2
area of incident, A = 5.2 cm² = 5.2 x 10⁻⁴ m²
Energy of incident photons per second on the given area;
E = IA
E = (2000)( 5.2 x 10⁻⁴)
E = 1.04 J/s
Energy of a photon is given is by;
The number of photons per second that strike the given area is;
Therefore, the number of photons per second that strike the given area is 2.668 x 10⁸ photons/second
<span>Low-level weapons production and Radioactive waste. hope that helped</span>