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Alexxx [7]
3 years ago
10

what will be the work done if a Unit chargeis moved from infinity to a distance 'R' from infinitely large charged sheet? CUT TO

POINT ANSWER PLEASE
Physics
1 answer:
fredd [130]3 years ago
4 0
We know, W = k. q₁q₂/ [1/r₁² - r₂² ]

Here, r₁ = R
r₂ = ∞

Substitute their values, 
 W = k. q₁q₂/ [1/R - 1/∞]
 W = k. q₁q₂/ [1/R]
 W = k. q₁q₂/ R

Hope this helps!
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Name the force between the brakes and the wheels that does work to slow down the vehicle when the brakes are applied. ​
suter [353]

Answer:

Friction

Explanation:

Because the brake pad is rubbing alongside the wheel to slow the body of the car down

3 0
3 years ago
A potter's wheel is rotating around a vertical axis through its center at a frequency of 2.0 rev/srev/s . The wheel can be consi
vagabundo [1.1K]

Answer:1.7 rev/s

Explanation:

Given

Frequency of wheel N_1=2\ rev/s

angular speed \omega_1=2\pi N_1=4\pi\  rad/s

mass of wheel m_1=4.5\ kg

diameter of wheel d_1=0.30\ m=30\ cm

radius of wheel r_1=\frac{d_1}{2}=\frac{30}{2}=15\ cm

mass of clay m_2=2.8\ kg

the radius of the chunk of clay r_2=8\ cm

Moment of inertia of Wheel

I_1=\dfrac{m_1r_1^2}{2}=\dfrac{4.5\times 15^2}{2}\ kg-cm^2

Combined moment of inertia of wheel and clay chunk

I_2=\dfrac{m_1r_1^2}{2}+\dfrac{m_2r_2^2}{2}=\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2}\ kg-cm^2

Conserving angular momentum

\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow \dfrac{4.5\times 15^2}{2}\cdot 4\pi=(\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2})\omega_2\\\\\Rightarrow \omega _2=\dfrac{4\pi }{1+\dfrac{2.8}{4.5}\times (\dfrac{8}{15})^2}=\dfrac{4\pi}{1+0.1769}=0.849\times 4\pi

Common frequency of wheel and chunk of clay is

\Rightarrow N_2=\dfrac{4\pi \times 0.849}{2\pi}=1.698\approx 1.7\ rev/s

5 0
3 years ago
What is the change in internal energy if 20 J of heat is released from a system and the system does 50 J of work on the surround
hjlf

The correct answer is a -80 J

3 0
3 years ago
Read 2 more answers
Which of the following relationships is correct?
masha68 [24]

Answer:

a. Relative humidity increases: a decrease in temperature without a change in the amount of water vapor in the atmosphere.

Explanation:

Colder air requires less humidity to saturate compared to warmer air. Therefore, the relative humidity depends on the air temperature. If the temperature drops and the water vapor content remains the same, relative humidity increases. If the temperature increases and the water vapor content remains the same, relative humidity decreases. Additionally, a greater amount of water vapor in the air increases the relative humudity.

3 0
3 years ago
What is her displacement
Aleks04 [339]

Answer:

c) 2 blocks

Explanation:

Her displacement is the difference between her starting point and her ending point.

Let's say she starts at the origin, (0, 0).

First, she goes 13 blocks east: (13, 0)

Next, she goes 4 blocks north: (13, 4)

Then she goes 8 blocks west: (5, 4)

Then she goes 6 blocks south: (5, -2)

Finally, she goes 5 blocks west: (0, -2)

The magnitude of her displacement is the distance between her initial and final positions: 2 blocks.

8 0
3 years ago
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