Answer:
<em>Correct answer: 2) 2p</em>
Explanation:
<u>Momentum</u>
Momentum is a measurement of mass in motion or how much mass is in how much motion. The symbol for momentum is p and is defined as:
p = m . v
Where m is the mass of the object and v is the speed. Note this is the scalar version of the formula because both p and v are vectors.
Suppose the mass of the object is doubled to 2m, then the new momentum is:
p' = (2m) . v = 2 m . v
Or, equivalently:
p' = 2p
Correct answer: 2) 2p
Here, we are given with:

(a) So now, we can thus obtain



Now, finding 


Now, finding k


Thus, expression for the electric field is:

(b) Now, here


Thus, expression for the magnetic field:

(c) The electromagnetic wave propagates along Z-axis
Answer:
15 V
Explanation:
Electric potential is given as the product of Electric field and distance. Mathematically:
V = E * r
Where E = Electric field
r = distance = 6m
Electric field, E, is:
E = F / q
Where F = Electric force = 5N
q = Electric charge = 2C
Therefore, electric potential will be:
V = (F * r) / q
V = (5 * 6) / 2
V = 15V
Answer:
Explanation:
STEP 1
<u>Given</u>
Radius of cylinder = r = 25cm, 2.5m
mass = 27kg
cylinder is mounted so as to rotate freely about a horizontal axis that is parallel to and 60cm to the central logitudinal axis of the cylinder
height = 0.6m
<u>part 1</u>
The cylinder is mounted so as to rotate freely about a horizontal axis tha is paralle to 60cm from the central longitudinal axis of then cylinder. The rotational inertia of the cylinder about the axis of rotation is given by
<em>I = Icm + mh²</em>
<em>∴ I = 1/2mr² + mh² = 1/2x27x (0.5)² + 20 x (0.6)²</em>
<em>I=13.09kg.m²</em>
where
<em>I</em>cm is the rotational inertia of the cylinder about its central axis
m is the mass of the cylinder
h is the distance between the axis of the rotation and the central axis of the cylinder
r is the radius of the cylinder
<em> </em><em> I=13.09kg.m²</em>
<em>part2</em>
<em>from the conservation of the total mechanical energy of the meter stick, the change in gravitational potential energyof the meter stick plus the change in kinetic energy must be zero</em>
<em>Δk + Δu = 0</em>
<em>1/2 </em>I(w²-w²) = Ui-Uf
1/2 x 13.09w² = mgh
∴w=√20 x 9.8 x 0.6/(1/2 x 13.09) =117.6/6.5
w=18.09rad/s
Answer: yes u can use a 6.75 when measuring the pencil