A rogue band of colonists on the moon declares war and prepares to use a catapult to launch large boulders at the earth. Assume
that the boulders are launched from the point on the moon nearest the earth. For this problem you can ignore the rotation of the two bodies and the orbiting of the moon.1) What is the minimum speed with which a boulder must be launched to reach the earth? Hint: The minimum speed is not the escape speed. You need to analyze a three-body system.2) Ignoring air resistance, what is the impact speed on earth of a boulder launched at this minimum speed?
1 answer:
Answer:
- 2.3 km/s
- 11 km/s
Explanation:
The system is made up of three body system which are the boulder, earth and the moon also the sum of potential ad kinetic energies are assumed to be the same also note that the boulder was launched from the moon at an initial velocity
A ) Minimum speed of the boulder for it to reach the earth = 2.3 km/s
B) ignoring air resistance the impact speed on earth of a boulder launched at this minimum speed = 11 km/s
find attached the solution in details
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The pressure increase at the bottom of the pool after they enter the pool and float is 106.103 Pa.
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given,
diameter = 6 m
depth = h = 1.5 m
Atmospheric pressure = P₀ = 10⁵ Pa
a) absolute pressure
P = P₀ + ρ g h
P = 10⁵ + 1000 x 10 x 1.5
P = 1.15 x 10⁵ Pa
b) When two person enters into the pool,
mass of the two person = 150 Kg
weight of water level displaced exists equal to the weight of person.
Area of pool
Height of the water rise
- Pressure increased
P = ρ g h
P = 1000 x 10 x 0.0106
P = 106.103 Pa
To learn more about absolute pressure refer to:
#SPJ4
Answer:
160N
Explanation:
Moments must be conserved - so.