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2 years ago

What are particles that are close together and locked in place??

Chemistry

1 answer:

Grace [21]2 years ago

3 0

Particles that are close together and locked in a place means its
a solid

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What are different type of plastids explain them?

BARSIC [14]

Answer:

Explanation:

There are 3 types of plastids :-

1) Chloroplasts:- The green plastids which contain chlorophyll pigments for photosynthesis.

2) Chromoplasts:-The coloured plastids for pigment synthesis and storage.

3) Leucoplasts:- The colourless plastids for monoterpene synthesis found in non- photosynthetic parts of the plants.

They are of three types:-

a) Amyloplasts- stores starch.

b) Proteinoplasts- stores proteins.

c) Elaioplasts- stores fats and oils.

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3 years ago

A solution containing aluminium ions reacts with a solution containing hydroxide ions to form a

Xelga [282]

Answer:

Explanation:

the answer is d white precipitate

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3 years ago

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In what type of reaction will an acid and a base react with each other

Arada [10]

When an acid and a base are placed together, they react to neutralize the acid and base properties, producing a salt. The H(+) cation of the acidcombines with the OH(-) anion of the base to form water.

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2 years ago

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For many years chloroform (CHCl3) was used as an inhalation anesthetic in spite of the fact that it is also a toxic substance th

Debora [2.8K]

Hey there!:

Molar mass:

CHCl3 = ( 12.01 * 1 )+ (1.008 * 1 ) + ( 35.45 * 3 ) => 119.37 g/mol

C% = ( atomic mass C / molar mass CHCl3 ) * 100

For C :

C % = (12.01 / 119.37 ) * 100

C% = ( 0.1006 * 100 )

C% = 10.06 %

For H :

H% = ( atomic mass H / molar mass CHCl3 ) * 100

H% = ( 1.008 / 119.37 ) * 100

H% = 0.008444 * 100

H% = 0.8444 %

For Cl :

Cl % ( molar mass Cl3 / molar mass CHCl3 ):

Cl% = ( 3 * 35.45 / 119.37 ) * 100

Cl% = ( 106.35 / 119.37 ) * 100

Cl% = 0.8909 * 100

Cl% = 89.9%

Hope that helps!

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3 years ago

What is the pOH of a 0.150 M solution of potassium nitrite? (Ka HNO2 = 4.5 x 10−4 )

yanalaym [24]

Answer:

11.9 is the pOH of a 0.150 M solution of potassium nitrite.

Explanation:

Solution : Given,

Concentration (c) = 0.150 M

Acid dissociation constant = $k_a=4.5\times 10^{-4}$

The equilibrium reaction for dissociation of $HNO_2$ (weak acid) is,

$HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+$

initially conc. c 0 0

At eqm. $c(1-\alpha)$ $c\alpha$ $c\alpha$

First we have to calculate the concentration of value of dissociation constant $(\alpha )$ .

Formula used :

$k_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}$

Now put all the given values in this formula ,we get the value of dissociation constant $(\alpha )$ .

$4.5\times 10^{-4}=\frac{(0.150\alpha)(0.150\alpha)}{0.150(1-\alpha)}$

$4.5\times 10^{-4} - 4.5\times 10^{-4}\alpha =0.150\alpha ^2$

$0.150\alpha ^2+4.5\times 10^{-4}\alpha-4.5\times 10^{-4}=0$

By solving the terms, we get

$\alpha=0.0533$

No we have to calculate the concentration of hydronium ion or hydrogen ion.

$[H^+]=c\alpha=0.150\times 0.0533=0.007995 M$

Now we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.007995 M)$

$pH=2.097\approx 2.1$

pH + pOH = 14

pOH =14 -2.1 = 11.9

Therefore, the pOH of the solution is 11.9

4 0

3 years ago