If a gas occupies 3.06 liters at 760 mm Hg, what will be the volume at a pressure of 1900 mm Hg?
1 answer:
1.22 litres will be the volume at a pressure of 1900 mm Hg if a gas occupies 3.06 liters at 760 mm Hg.
Explanation:
Data given:
Initial volume of the gas V1 = 3.06 Litres
Initial pressure of the gas P1 = 760 mm Hg
final pressure of the gas P2 = 1900 m Hg
final volume of the gas V2 =?
From the data we can see that Boyle's Law will be applied here,
P1V1 = P2V2
Rearranging the equation, we get
V2 =
putting the values in the equation, we get
V2 =
V2 = 1.224 Litres
The volume is 1.22 litres when the pressure is increased to 1900 mmHg.
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Answer:
The value of Kp at this temperature is 7.44*10⁻³
Explanation:
Chemical equilibrium is established when there are two opposite reactions that take place simultaneously at the same speed.
For the general chemical equation for a homogeneous gas phase system:
aA + bB ⇔ cC + dD
where a, b, c and d are the stoichiometric coefficients of compounds A, B, C and D, the equilibrium constant Kp is determined by the following expression:
Where Px is the partial pressure of each of the components once equilibrium has been reached and they are expressed in atmospheres. The equilibrium constant Kp depends solely on temperature and is dimensionless.
In the case of the reaction:
2 HI (g) ⇔ H₂ (g) + I₂ (g)
the equilibrium constant Kp is determined by the following expression:
The system comes to equilibrium at 425 °C, and
- PHI = 0.794 atm
- PH2 = 0.0685 atm
- PI2 = 0.0685 atm
Replacing:
Kp=7.44*10⁻³
<u><em>The value of Kp at this temperature is 7.44*10⁻³</em></u>