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Mamont248 [21]
3 years ago
11

If a gas occupies 3.06 liters at 760 mm Hg, what will be the volume at a pressure of 1900 mm Hg?

Chemistry
1 answer:
OleMash [197]3 years ago
7 0

1.22 litres will be the volume at a pressure of 1900 mm Hg if a gas occupies 3.06 liters at 760 mm Hg.

Explanation:

Data given:

Initial volume of the gas V1 = 3.06 Litres

Initial pressure of the gas P1 = 760 mm Hg

final pressure of the gas  P2 = 1900 m Hg

final volume of the gas V2 =?

From the data we can see that Boyle's Law will be applied here,

P1V1 = P2V2

Rearranging the equation, we get

V2 = \frac{P1V1}{P2}

putting the values in the equation, we get

V2 = \frac{3.06 X 760}{1900}

V2 = 1.224 Litres

The volume is 1.22 litres when the pressure is increased to 1900 mmHg.

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<em>The three gases, in the three identical containers, will all have the same number of molecules</em>

Explanation:

If these three gases (Helium He, Neon Ne, and Oxygen O_{2}) are all contained in separate identical containers with the same volume. And they are all stored at the same temperature, and pressure. Then, they'll all contain the same number of molecules. This is in line with Avogadro's law which states that "Equal volume of all gases, at the same temperature and pressure, have the same number of molecules."

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In naming the compound PCl5, the prefix used with the second element is ____________________.
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Answer:

\boxed {\boxed {\sf Hepta}}

Explanation:

We are given the formula:

PCl_5

This is a molecular formula, because it contains nonmetals.

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2. Second element

The second element is chlorine (Cl). It has a subscript of 5, so we must add the prefix of <u>hepta</u>-.

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Add the ending of -ide.

  • Phosphorous heptachloride

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How many electrons are in O2-?
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Read 2 more answers
Ca(OH)2 (s) precipitates when a 1.0 g sample of CaC2(s) is added to 1.0 L of distilled water at room temperature. If a 0.064 g s
Nina [5.8K]

Answer:

D) Ca(OH)₂ will not precipitate because Q <  Ksp

Explanation:

Here we have first a chemical reaction in which Ca(OH)₂  is produced:

CaC₂(s)  + H₂O ⇒ Ca(OH)₂ + C₂H₂

Ca(OH)₂  is slightly soluble, and depending on its concentration it may precipitate out of solution.

The solubility product  constant for Ca(OH)₂  is:

Ca(OH)₂(s) ⇆ Ca²⁺(aq) + 2OH⁻(aq)

Ksp = [Ca²⁺][OH⁻]²

and the reaction quotient Q:

Q = [Ca²⁺][OH⁻]²

So by comparing Q with Ksp we will be able to determine if a precipitate will form.

From the stoichiometry of the reaction we know the number of moles of hydroxide produced, and since the volume is 1 L the molarity will also be known.

mol Ca(OH)₂ = mol CaC₂( reacted = 0.064 g / 64 g/mol = 0.001 mol Ca(OH)₂

the concentration of ions will be:

[Ca²⁺ ] = 0.001 mol / L 0.001 M

[OH⁻] = 2 x 0.001 M  = 0.002 M  ( From the coefficient 2 in the equilibrium)

Now we can calculate the reaction quotient.

Q=  [Ca²⁺][OH⁻]² = 0.001 x (0.002)² = 4.0 x 10⁻⁹

Q < Ksp since 4.0 x 10⁻⁹ < 8.0 x 10⁻⁸

Therefore no precipitate will form.

The answer that matches is option D

8 0
3 years ago
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