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Otrada [13]
4 years ago
6

The square root of 728

Mathematics
1 answer:
Tema [17]4 years ago
4 0

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

The square root of 728 is 269.

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ May ♡

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Expand the expression 1/2 (3+4t-10)
Alex73 [517]

Answer:3/2 + t - 5

Step-by-step explanation:

1/2(3+4t-10)

Open brackets

3/2 + 4t/2 - 10/2

3/2 + t - 5

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3 years ago
Two random variables x and y are independent if the value of x does not affect the value of y. If the variables are not​ indepen
jeyben [28]

Answer: \mu_{x+y} = 3026

              \mu_{x-y}= 30

Step-by-step explanation: Average sum of the female and male's test score is the sum of expected value of each gender:

\mu_{x+y}=\mu_{x}+\mu_{y}

Assuming x represents the random male selected and y represents the random female selected:

\mu_{x+y}=1528+1498

\mu_{x+y}= 3026

The average sum of their scores is 3026.

Average difference is the difference between the expected value (mean) of each gender:

\mu_{x-y}=\mu_{x}-\mu_{y}

\mu_{x-y}= 1528 - 1498

\mu_{x-y}= 30

The average difference of their scores is 30.

6 0
3 years ago
An older person is 8 years older than seven times the age of a younger person. The sum of their ages is 32. What are their ages?
tatiyna

Answer:

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3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

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