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deff fn [24]
4 years ago
13

Force F acts on the frame such that its component acting along member AB is 650 lb, directed from B towards A. Determine the req

uired angle f (0 … f … 45) and the component acting along member BC. Set F = 850 lb and u = 30.

Physics
1 answer:
jeyben [28]4 years ago
8 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The angle is 33.54°

The component acting along member BC is F_{BC} = 433.638\ lb

Explanation:

The explanation is shown on the second uploaded image

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There is a bell at the top of a tower that is 95 m high. The mass of the bell is 21 kg. What is the potential energy of the bell
melomori [17]

Answer:

19,551 J!

Explanation:

The formula is PE = ham (h=height, a= acceleration or 9.8, m= mass)

PE = (95)(9.8)(21)

PE = 19,551 Joules

5 0
3 years ago
If the flea jumps straight up, how high will it go? (Ignore air resistance for this problem; in reality, air resistance plays a
Savatey [412]

Answer:

The flea will reach to a height of 5.2 cm.

Explanation:

Let us assume it is given that, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.50 mm.

Initial speed, u = 1 m/s

Initial distance, x = 0.5 mm

We need to find the height reached by the flea. Using third equation of motion to find it.

At maximum height, its final speed, v = 0

v^2-u^2=2ah

Here, a = -g

-u^2=-2g(h-x)\\\\1^2=2\times 9.8\times (h-0.5\times 10^{-3})\\\\h=0.052\ m

or

h = 5.2 cm

So, the flea will reach to a height of 5.2 cm.

6 0
3 years ago
Examine the scenario.
vovangra [49]

Answer:

acceleration 8 km/h/s south

Explanation:

First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.

Based on this definition, we can already rule out the following two choices:

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speed: 40 km/h

Since they only have magnitude, they are not vectors.

Then, the following option:

velocity: 5 km/h north

is wrong, because the car is moving south, not north.

So, the correct choice is

acceleration 8 km/h/s south

In fact, the acceleration can be calculated as

a=\frac{v-u}{t}

where

v = 40 km/h is the final velocity

u = 0 is the initial velocity

t = 5 s is the time

Substituting,

a=\frac{40 km/h-0}{5 s}=8 km/h/s

And since the sign is positive, the direction is the same as the velocity (south).

7 0
4 years ago
A 0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary fo
frutty [35]

Answer:

90 N

Explanation:

The force applied to the ball is given by:

F=\frac{\Delta p}{\Delta t}

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\Delta p is the change in momentum of the ball

\Delta t is the time taken

The change on momentum of the ball is:

\Delta p=m\Delta v=(0.45 kg)(20 m/s)=9 kg m/s

So, the force applied is

F=\frac{9 kg m/s}{0.10 s}=90 N

6 0
3 years ago
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icang [17]

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I think it's D.,,,,,,,,

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