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Ipatiy [6.2K]
3 years ago
12

There is a bell at the top of a tower that is 95 m high. The mass of the bell is 21 kg. What is the potential energy of the bell

?
Physics
1 answer:
melomori [17]3 years ago
5 0

Answer:

19,551 J!

Explanation:

The formula is PE = ham (h=height, a= acceleration or 9.8, m= mass)

PE = (95)(9.8)(21)

PE = 19,551 Joules

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NeTakaya

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3 years ago
The football player running towards the goal line has
blagie [28]

the football player has speed

8 0
3 years ago
Read 2 more answers
1. 412.9 g of dry ice sublimes at room temperature. a. What’s changing? --- sublimation b. What constant will you use? ----- 25.
hoa [83]

1. 236 kJ

a. The phase (or state of matter) of the substance: from solid state to gas state (sublimation)

b. The enthalphy of sublimation, given by: \lambda=571 J/g

c. The equation to use will be Q=m\lambda, where m is the mass of dry ice and \lambda is the enthalpy of sublimation

d. The energy is being absorbed, because the heat is transferred from the environment to the dry ice: as a consequence, the bonds between the molecules of dry ice break and then move faster and faster, and so the substance turns from solid into gas directly.

e. The amount of energy being transferred is

Q=m\lambda=(412.9 g)(571 J/g)=2.36\cdot 10^5 J=236 kJ

2.  165 kJ

a. The phase (or state of matter) of the substance: from gas state to liquid state (condensation)

b. The latent heat of vaporisation of water, given by \lambda=2260 J/g

c. The equation to use will be Q=m\lambda, where m is the mass of steam that condenses and \lambda is the latent heat of vaporisation

d. The energy is being released, since the substance turns from a gas state (where molecules move faster) into liquid state (where molecules move slower), so the internal energy of the substance has decreased, therefore heat has been released

e. The amount of energy being transferred is

Q=m\lambda=(72.9 g)(2260 J/g)=1.65\cdot 10^5 J=165 kJ

3. 3.64 kJ

a. Only the temperature of the substance (which is increasing)

b. The specific heat capacity of silver, which is C_s = 0.240 J/gC

c. The equation to use will be Q=m C_s \Delta T, where m is the mass of silver, Cs is the specific heat capacity and \Delta T the increase in temperature

d. The energy is being absorbed by the silver, since its temperature increases, this means that its molecules move faster so energy should be provided to the silver by the surroundings

e. The amount of energy being transferred is

Q=m C_s \Delta T=(39.2 g)(0.240 J/gC)(412.9^{\circ}C-25.9^{\circ}C)=3641=3.64 kJ

4. 89 kJ

a. Both the phase of the substance (from solid to liquid) and then the temperature

b. The latent heat of fusion of ice: \lambda=334 J/g and the specific heat capacity of water: C_s=4.186 J/gC

c. The equation to use will be Q=m\lambda + m C_s \Delta T, where m is the mass of ice, \lambda the latent heat of fusion of ice, Cs is the specific heat capacity of water and \Delta T the increase in temperature

d. The energy is being absorbed by the ice, at first to break the bonds between the molecules of ice and to cause the melting of ice, and then to increase the temperature of the water

e. The amount of energy being transferred is

Q=m\lambda +m C_s \Delta T=(156.3 g)(334 J/g)+(156.3 g)(4.186 J/gC)(56.232^{\circ}C-0^{\circ}C)=8.9\cdot 10^4 J=89 kJ

6 0
3 years ago
A book is sliding along a desk top. Because the book is in motion ,you know that the forces acting on the book are A. Balanced B
Virty [35]
Just because the book is moving doesn't tell you anything about the forces on it, or even whether there ARE any.

Just look at Newton's first law of motion, and this time, let's try and THINK about it too. It says something to the effect that any object continues in constant, uniform MOTION ..... UNLESS acted on by an external force.
4 0
4 years ago
2. Classify Identify the following materials as thermal conductors or
Elenna [48]
Answer -
Wooden spoon: thermal insulator
Iron frying pan: thermal conductor
Plastic spatula: thermal insulator
Steel fork: thermal conductor

Hope this helps
5 0
3 years ago
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