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AleksAgata [21]
3 years ago
11

Is the answer 0.055 seconds? (Only problem 13)

Physics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

98.7 seconds

Explanation:

I believe the answer is not 0.055s

Both trains have the same speed and are approaching each other.

They both have to cover 8.5km, and since they are going the same speed they need to cover half the distance each (4.25km)

So, how long will it take a train going 155km/h to travel 4.25km?

The ratio of

<h2>\frac{155km}{1hour}  = \frac{4.25km}{x hours}</h2>

There are 60 x 60 seconds in one hour (3600 seconds)

\frac{155km}{3600 seconds}  = \frac{4.25km}{x seconds}

Solve for x to get 98.7 seconds

We can do this by flipping both sides of the ratio

\frac{3600 s}{155 km}  = \frac{x seconds}{4.25 km}

Multiply both sides by 4.25km

4.25 ×  \frac{3600 s}{155 km}  ={x seconds}

Our unknown x = 98.7 seconds

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Answer:

Force of kinetic friction, Fk = 6N

Explanation:

Given the following data;

Coefficient of kinetic friction, μ = 0.2

Normal force, Fn=30N

To find the Force of kinetic friction;

Mathematically, the force of kinetic friction is given by the formula;

Fk = μFn

Where;

  • Fk represents the force of kinetic friction.
  • μ represents the coefficient of friction.
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Substituting into the equation, we have;

Fk = 0.2*30

Fk = 6N

Therefore, the force of kinetic friction is 6N.

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Answer:

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Explanation:

The first thing to take into account is that the stored energy in a battery is in Watts per second or Joules (W\cdot s=J). It means that the battery provides a power for a certain time.

The idea is to know how much W\cdot s has been consumed by the circuit.

The first step is to know the power that is consumed by the circuit. It is P=V\cdot I. The problem says that the circuit consumes a current of 5.0A with a voltage of 6.0V. It means that the power consumed is:

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The previous value (30W) is the power that the circuit consumes.

Now, you must find the total amount of power that is consumed by the circuit in 6.0 minutes. You just have to multiply the power that the circuit consumed by the time it worked, it means, 6.0 minutes.

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You must convert the minutes unit to seconds. Remember that 1 minute has 60 seconds.

energy=P\cdot t=(30W)\cdot (6.0min) \cdot \frac{60s}{1min}=10800W\cdot s=10800J

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