<em>Let the common root is ‘x’</em>
<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)</em>
<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)</em>
<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get</em>
<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0</em>
<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0⇒ x = (a-b)/(a-b) = 1</em>
<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0⇒ x = (a-b)/(a-b) = 1⇒ x = 1</em>
<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0⇒ x = (a-b)/(a-b) = 1⇒ x = 1⇒ {1 + a + b = 0} (From equation (1))</em>
<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0⇒ x = (a-b)/(a-b) = 1⇒ x = 1⇒ {1 + a + b = 0} (From equation (1))⇒ a + b = –1</em>
Answer: 3/4 is larger
Step-by-step explanation: 3/4 is larger than 2/3
Answer:
So the maximum amount of gasoline the tank can contain is 13 gallons and there are already 7 gallons of gasoline in the tank. Therefore, we want to make sure that the amount of gasoline put in the tank doesn't reach any higher than 13 gallon.
The amount of gasoline that Lou bought with x dollars is x/2.50 gallons.
We have the inequality:
x/2.50 + 7 ≤ 13
*If you solve it, x should be smaller or equal to $15.
It is the 3rd statement because although it goes through the origin, it is not a straight line.
When given the first 3 points, you can conclude that the line would be y=3x (linear), however, the 4th point doesn't lie along the line so it is not linear. This is shown in the attachment where the blue line is y=3x and the 4 dots are the points given.