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densk [106]
4 years ago
5

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

Mathematics
1 answer:
wolverine [178]4 years ago
4 0

<em>See</em><em> </em><em>above</em><em> </em><em>graph</em>

I am joyous to assist you anytime.

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Help please!<br> please make the answers original.
baherus [9]

Answer:

I will do it but what is the GCF of part B

Step-by-step explanation:

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3 years ago
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Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4
lesya692 [45]

The empirical rule says that roughly 99.7% of the population is within 3 standard deviations of the mean.

Start at the center 60 which is the mean. Add on 3 standard deviations

60 + 3*4.5 = 73.5

and subtract off 3 standard deviations from the mean

60 - 3*4.5 = 46.5

So roughly 99.7% of the population of cattle has horn lengths between 46.5 inches and 73.5 inches

<h3>Answer: Choice D. 46.5 in - 73.5 in</h3>
4 0
4 years ago
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A bag contains 5 black, 3 green, 3 blue, and 4 yellow marbles. A marble is randomly drawn. Find P(not black). 4/15 1/5 1/3 2/3
QveST [7]

Answer:

2/3

Step-by-step explanation:

5 black

3 green (not black)

3 blue (not black)

4 yellow (not black)

there are 5 black and 10 not black out of a total of 15 marbles.

there are 10/15 that are not black.  Reduced 2/3.

6 0
3 years ago
Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position
nexus9112 [7]

Answer:

\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60

Step-by-step explanation:

So, we know that:

\tan(\theta)=60/11\text{ and } 90\textdegree

Since θ is in QI, this means that <em>all</em> of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the <em>opposite side to the adjacent side</em>. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

a^2+b^2=c^2

Substitute 60 for a and 11 for b:

60^2+11^2=c^2

Solve for c. Square both numbers:

3600+121=c^2

Add:

c^2=3721

Take the square root of both sides:

c=61

Therefore, the hypotenuse is 61.

So, our side lengths are: Opposite=60; Adjacent=11; and Hypotenuse=61.

Now that we know the lengths, we can find the other trig ratios:

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 60 for Opp and 61 for Hyp:

\sin(\theta)=60/61

Cosecant is the reciprocal of sine. So:

\csc(\theta)=61/60

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 11 for Adj and 61 for Hyp:

\cos(\theta)=11/61

Secant is the reciprocal of cosine. So:

\sec(\theta)=61/11

Tangent and Cotangent:

We are already given that tangent is:

\tan(\theta)=60/11

Cotangent is the reciprocal of tangent. So:

\cot(\theta)=11/60

4 0
4 years ago
17 divided by 476 partial quotient
disa [49]
It's about 0.03571

I think that's what you're looking for
6 0
4 years ago
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