1 Na = 23 g/mol
1 mole of Na atom contain an Avogadro Number of atoms .
23g of Na Na atom contain 6.02 * 10²³ atoms.
175 g of Na will contain: 175 * <span>6.02 * 10²³ / 23
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≈ 4.580 * 10²⁴ atoms of Na.
It's just the chemistry that works without Carbon
I remember sth like that
Answer: C. 112 grams
Using the law of conservation of mass, you can say that the total mass of the reactant would be equal to total mass of the product. The reactant of this reaction would be 200g CaCO3(calcium carbonate). The product would be x g <span>calcium oxide(CaO) and 88g carbon dioxide(CO2). The calculation would be:
reactant = product
200g= 88g+ x
x= 200g-88g= 112g
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4K + O₂ ⇒ 2K₂O
4mol : 2mol
1,52mol : x
x = 1,52mol*2mol / 4mol = 0,76mol