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Alborosie
3 years ago
9

Which state of matter characterized by having a definite shape and a definite volume?

Chemistry
1 answer:
blagie [28]3 years ago
7 0
Solid. Water doesn't have a definite shape. Gas doesn't have either.
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In a calorimetry experiment, a salt is dissolved in water within an insulating container. The temperature of the solution (surro
Stels [109]

Answer:

Explanation:

heat released  by the solution

= 120 x 3.18 x ( 25 - 14 )

= 4197.6 J

= 4.1976 kJ

This is the heat gain by the salt

so enthalpy change = +  4.1976 kJ

because there is increase  in enthalpy

It is endothermic process .

7 0
3 years ago
If a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay, what will be the new element?
Charra [1.4K]

Answer:

The new element will be thorium-226 (²²⁶Th).

Explanation:

The beta decay is given by:

^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + \beta^{-} + \bar{\nu_{e}}

Where:

A: is the mass number

Z: is the number of protons  

β⁻: is a beta particle = electron

\bar{\nu_{e}}: is an antineutrino

The neutral atom has 88 electrons, so:

e^{-} = 88 = Z

Hence the element is radium (Ra), it has A = 226.

If Ra undergoes 2 rounds of beta minus decay, we have:

^{226}_{88}Ra \rightarrow ^{226}_{89}Ac + \beta^{-} + \bar{\nu_{e}}    

^{226}_{89}Ac \rightarrow ^{226}_{90}Th + \beta^{-} + \bar{\nu_{e}}

Therefore, if a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay the new element will be thorium-226 (²²⁶Th).

I hope it helps you!    

8 0
2 years ago
I NEED HELP KNOW LAST QUESTION ON MY TEST
RoseWind [281]

Answer:  

Explanation: In my opinion  law is stated as fact because it is passes through and approved by many peoples but theory is an idea someone has and is not approved and is set on a base of beliefs.

8 0
3 years ago
Read 2 more answers
ALUMINUM (AI)<br> + NITRATE (NO3)
anzhelika [568]

Answer:

Al(No3)3

Explanation:

hope this is correct....

7 0
2 years ago
when copper sulfide is partially roasted in air (reaction with o2), copper sulfite is formed first. subsequently, upon heating,
Lyrx [107]

The question is incomplete, complete question is:

When copper(I) sulfide is partially roasted in air (reaction with oxygen), copper(I) sulfite is formed first. subsequently, upon heating, the copper sulfite thermally decomposes to copper(I) oxide and sulfur dioxide. Write balanced chemical equations for these two reactions.

Answer:

The balanced chemical equations for these two reactions:

2Cu_2S(s)+3O_2(g)\rightarrow 2Cu_2SO_3(s)

Cu_2SO_3(s)\overset{heat}\rightarrow Cu_2O(s)+SO_2(g)

Explanation:

On  partial roasting of copper sulfide in an air. The balanced chemical reaction is given as:

2Cu_2S(s)+3O_2(g)\rightarrow 2Cu_2SO_3(s)

On further heating of copper(I) sulfite it get decomposes into copper oxide and sulfur dioxide. The balanced chemical reaction is given as:

Cu_2SO_3(s)\overset{heat}\rightarrow Cu_2O(s)+SO_2(g)

5 0
3 years ago
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