The mass of the sample reported is 3.5465 g option e is correct.
Mass is the quantitative measure of the physical body.
The mass of the empty sample container is given as 12 g.
The mass of empty as well as sample containers is given as 15.5465 g.
Therefore, the mass of the sample will be given as :
Mass of sample = mass of a sample as well as empty containers - a mass of empty sample container
= 15.5465 - 12
= 3.5465 g
Therefore, the mass of the sample reported is 3.5465 g option e is correct.
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# SPJ4
Complete question:
Your question is incomplete, but most probably your full question was, A label on an empty sample container reads 12.00 g. you add in a sample of a compound and the mass of the sample container obtaining 15.5465 g. what should the mass of the sample be reported as?
a) 3.546 g
b) 3.54 g
c) 4 g
d) 4.0 g
e) 3.5465 g
Answer:
condensation reaction
Explanation:
In condensation reaction is a small molecule formed from the atoms removed from a single reactant molecule
Answer:
Explanation:
Assume the reaction is the combustion of propane.
Word equation: propane plus oxygen produces carbon dioxide and water
Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)
Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)
(a) Table of enthalpies of formation of reactants and products
(b)Total enthalpies of reactants and products
ΔᵣH° is negative, so the reaction is exothermic.
It leads up to the climax.
Answer:
The formula of Al³⁺ and SO₄²⁻ is aluminum sulfate.
Explanation:
The formula for aluminum sulfate is Al₂(SO₄)₃. If we say in terms of ions. The ions are Al³⁺. It is a positive ion or the cation. Other ion is SO₄²⁻. It is sulfate ion. It is anion.
Aluminum sulphate is used in water purification and as a mordant in dyeing and printing textiles.
Hence, the formula of Al³⁺ and SO₄²⁻ is aluminum sulfate.
