To determine which is the correct answer, we convert the mass of the compounds into units of particles of the compound. We use the molar masses and the Avogadro's number. We do as follows:
<span>76.9 g I2 (1 mol / 253.81 g) (6.022x10^23 particles / 1 mol ) = 1.82x10^23
79.9 g Br2 (1 mol / 159.81 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>
6 g C (1 mol / 12 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>
13.01 g CH4 ( 1 mol / 16.04 g )</span>(6.022x10^23 particles / 1 mol ) = 4.88x10^23 particles
Therefore, the answers are Br2 and C.
Answer:
25cm³ = 0.025L of H2So4
Molarity of H2SO4 = 1moldm-³
Recall ... 1dm-³ = 1L
So the Molarity can also be 1mol/L
Mole = Molarity x volume in L
Mole of H2SO4 = 1mol/L x 0.025L
=0.025Moles of Sulphuric acid reacted.
From the equation of reaction
1mole of H2SO4 reacts to produce 1mole of Copper sulphate crystal
Since their Mole ratio is 1:1
It means that Since 0.025mole of H2SO4 reacted.... 0.025mole of CuSO4.5H2O would be produced
Nice.. OK
So we know the moles of CuSO4.5H2O produced
We can get the Mass
Recall
From
Mole=Mass/Molar Mass
Mass = Mole x Molar Mass
Molar Mass of CuSO4.5H2O = 64 + 32 + 16x4+ 5(2+16)
Mm= 250g/mol
Mass = 0.025mol x 250g/mol
= 6.25g of CuSO4.5H2O crystals Would be PRODUCED.
Answer:
Explanation:
Aly's teacher said some bacteria can be as small as 0.00365 cm long.
In this problem, we need to write the length of the bacteria written in scientific notation. Any number can be written in the form of scientific notation as follows :
a is a real no and b is an integer
In the given number, there are two zeroes before 3. We need to shift the decimal after 3. It can be done as follows :
Hence, this is the required solution.
Answer:
A molecule of water has two hydrogen atoms. Both of these atoms can form a hydrogen bond with oxygen atoms of different water molecules. Every water molecule can be hydrogen bonded with up to three other water molecules
