It’s hard which class are u
Answer:
Al°(s) + 3Ag⁺(aq) => Al⁺³(aq) + 3Ag(s)
Explanation:
Oxidation: Al°(s) => Al⁺³(aq) + 3e⁻
Reduction: 3Ag⁺(aq) + 3e⁻ => 3Ag°(s)
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Net Rxn: Al°(s) + 3Ag⁺(aq) => Al⁺³(aq) + 3Ag(s)
One mole of neutral aluminum atoms (Al°(s)) undergo oxidation delivering 3 moles of electrons to 3 moles silver ions (3Ag⁺³(aq)) that are reduced to 3 moles of neutral silver atoms (3Ag°(s)) in basic standard state 25°C; 1atm.
Hey there!
Magnesium chlorate: Mg(ClO₃)₂
Find molar mass.
Mg: 1 x 24.305 = 24.305
Cl: 2 x 35.453 = 70.906
O: 6 x 16 = 96
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191.211 g/mol
We have 187.54 grams.
187.54 ÷ 191.211 = 0.9808
There are 0.9808 moles in 187.54 grams of magnesium chlorate.
Hope this helps!