Sound waves are D) Mechanical and Longitudinal
Explanation:
In physics, waves are classified into two types:
- Mechanical waves are those waves that need a medium to propagate - these waves are produced by the vibrations of the particles of the medium
- Electromagnetic waves are produced by the alternating vibrations of electric and magnetic fields - they are the only waves that can also travel through a vacuum, so they do not need a medium
Moreover, waves are further classified into:
- Transverse waves are those in which the vibration of the wave occurs in a direction perpendicular to the direction of propagation of the wave
- Longitudinal waves are those in which the vibration of the wave is parallel (back and forth) to the direction of propagation of the wave
Sound waves are oscillations of a medium that occurs back-and forth along the direction of propagation of the wave. Therefore, they are mechanical (they need a medium to propagate) and longitudinal. So the correct answer is
D) Mechanical and Longitudinal
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Answer:
He means Explain the differences between mix and match. Give one example of each.
Explanation:
Answer: D. They turn red litmus paper blue and taste bitter.
Explanation:
Acids are those substances which either donates hydrogen ions when dissolved in water. They have pH ranging from 1 to 6.9. They are sour in taste. They dissolve metals to give hydrogen gas. They turn blue litmus red.
Bases are those substances which either donates hydroxide ions when dissolved in water or donates a pair of electrons. They have pH ranging from 7.1 to 14. They are bitter in taste. They are slippery in nature. They turn red litmus blue.
Hello!
To find the amount of energy need to raise the temperature of 125 grams of water from 25.0° C to 35.0° C, we will need to use the formula: q = mcΔt.
In this formula, q is the heat absorbed, m is the mass, c is the specific heat, and Δt is the change in temperature, which is found by final temperature minus the initial temperature.
Firstly, we can find the change in temperature. We are given the initial temperature, which is 25.0° C and the final temperature, which is 35.0° C. It is found by subtract the final temperature from the initial temperature.
35.0° C - 25.0° C = 10.0° C
We are also given the specific heat and the grams of water. With that, we can substitute the given values into the equation and multiply.
q = 125 g × 4.184 J/g °C × 10.0° C
q = 523 J/°C × 10.0° C
q = 5230 J
Therefore, it will take 5230 joules (J) to raise the temperature of the water.
