The given chemical reaction is:
Δ∑BE(reactants)-∑BE(products)
= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]
= 467 kJ/mol
Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:
Moles of chlorine =
= 1.20 mol
Heat change when 1.20 mol chlorine reacts
=
Iodine 131 and iodine 126 are the same in the sense that, they both have the same number of electrons and protons in their atoms, it is only the number of their neutrons that is different. Iodine 131 has 78 neutrons while iodine 126 has 73 neutrons.
Answer:
Contact
Explanation:
As the particles heat up, they move around more, resulting in them hitting the sides of the container more.
<span>It relates the </span>measured<span> cell </span>potential<span> to the reaction quotient and allows the ... Substituting these expressions into Equation 20.6.</span>1<span>, we obtain ... the </span>standard<span> cell </span>potential<span> (E° cell), and the </span>reactant<span> and product concentrations at ... 0.013 </span>M, [Ce3+<span>] = 0.60 </span>M, [Cl−<span>] = 0.0030 </span>M, PC<span>l2 = 1.0 atm, and T = </span>25°C<span>.</span>
Answer:
its down below
Explanation:
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