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3 years ago

What is the simplest form of matter that can exist under lab conditions

Chemistry

1 answer:

neonofarm [45]3 years ago

6 0

Elementssimplest form of matter that can exist under normal laaboratory conditions

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A balloon is filled to a volume of 1.6 L at 278 K. The balloon is left outside overnight and the temperature has dropped to 253

german

Explanation:

Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,

Volume ∝ Temperature

i.e. $\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{1.6\times 253}{278}\\\\V_2=1.45\ L$

So, the new volume is 1.45 L.

6 0

3 years ago

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa

notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

$2NaOH+H_2SO_4-->Na_2SO_4+2H_2O$

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

$n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\$

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

$0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4$

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

$0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4$

Finally, the percent yield turns out into:

$Y=\frac{1.92g}{7.1g} *100$

$Y=27.0$ %

Best regards.

6 0

2 years ago

Disadvantages of modern periodic table?

ira [324]

Answer:

It has its elements with mass numbers phrased in many decimal places, it requires one to round off to get the actual value.

The atomic numbers of some elements such as Protonium were just guessed.

4 0

2 years ago

The solubility of kL is 50g in 100 g h2o at 20 celcius. If 110 grams of of kL are added to 200 grams of h2o. What is happens ?

tia_tia [17]

Answer:

a saturated solution will form.

Explanation:

All solutions have a definite capacity of dissolving solute in it.

Unsaturated solutions are the solutions which contain less amount of solute than the maximum capacity of dissolving the solute. If more amount of solute is added in such a way a point is reached where addition of more solute cannot be dissolved. The solution is known as saturated solution.

Amount dissolved > Maximum solubility limit, the solution is saturated.

Amount dissolved < Maximum solubility limit, the solution is unsaturated.

If the amount of the salt exceeds the solubility limit, then the solution is saturated solution. If it is less than the limit given, then it is unsaturated solution.

Given,

50 g of KI is added to 100 g of water at 20 °C.

It means:

100 g of water can dissolve maximum of 50 g of KCl.

Also,

1 g of water can dissolve maximum of 0.5 g of KCl.

To check for 200 g of water:

200 g of water can dissolve maximum of (0.5)*200 g of KCl.

Maximum amount of KCl that can be dissolved = 100 g

Actual amount dissolved = 110 g

Since,

Amount dissolved > Maximum solubility limit

110 g > 100 g

According to definition, the solution is saturated.

Hence, a saturated solution will form.

3 0

3 years ago

the compound sodium sulfide consists of a ratio of two sodium ions (Na+) to one sulfide ion (Sa-). write the chemical formula fo

Brut [27]

Answer:

Na₂S

Explanation:

3 0

3 years ago