All categories

3 years ago

What is the simplest form of matter that can exist under lab conditions

Chemistry

1 answer:

neonofarm [45]3 years ago

6 0

Elements<span>simplest form of matter that can exist under normal laaboratory conditions</span>

You might be interested in

Balance the following reaction:

miv72 [106K]

The balanced reaction is as below

3A₂B + 2DC₃→ 6 AC + D₂B₃

The number that must be to the left of AC is 6

Explanation

According to the law of mass conservation , the number of atoms in reactant side must be equal to number to the number of atoms in product side.

Therefore the equation above is balance since it obey the law of mass conservation.

For example there is 6 atoms of A in reactant side and 6 in product side.

5 0

3 years ago

Read 2 more answers

How much heat is needed to boil 45 grams of water at 100°C?

wolverine [178]

Answer:

Depends how much water and the temperature of the water. To heat 1 mL of water by 1 degree C 1 cal of energy (4.184 Joules) is required. Assuming that the water is at 25 degrees C, to boil one litre (liter) of water you would require 75,000 cal or 313.8 kJ.

6 0

3 years ago

Which determines the frequency of a sound wave? A the intensity of the sound waves B the rate at which the sound source is vibra

andreyandreev [35.5K]

Answer:

Explanation:

The number of vibrations per second is known as the frequency

7 0

3 years ago

Read 2 more answers

A fecal transplant can work to cure a patient infected with a very harmful bacteria, such as C. difficile.

Dmitrij [34]

Answer: Bacteria from the fecal transplant can fill up the space in the gut, limiting the food and space for invading harmful bacteria.fecal transplants may be best answer to antibiotic-resistant bacteria: Non-pharmaceutical treatment combats recurring Clostridium Difficile infections

Explanation:

4 0

3 years ago

Methyl salicylate is a common active ingredient in liniments such as ben-gay. It is also known as oil of wintergreen. It is made

arlik [135]

Answer: The empirical formula is $C_3H_3O$ .

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2$ = 12.24 g

Mass of $H_2O$ = 2.505 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 12.24 g of carbon dioxide, = $\frac{12}{44}\times 12.24=3.338g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.505 g of water, = $\frac{2}{18}\times 2.505=0.278g$ of hydrogen will be contained.

Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{1.671g}{16g/mole}=0.104moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.278}{0.104}=3$

For H = $\frac{0.278}{0.104}=3$

For O = $\frac{0.104}{0.104}=1$

The ratio of C : H : O = 3: 3: 1

Hence the empirical formula is $C_3H_3O$ .

5 0

3 years ago