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3 years ago

What is the value of x in -x + 8 > 6 ?

Mathematics

1 answer:

makvit [3.9K]3 years ago

8 0

Step-by-step explanation:

$- x + 8 > 6 \\ - x > - 2 \\ x < 2$

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Find the solution <br><br><br> 3(x - 4)+ 2x =23

horsena [70]

Answer:

the answer for that is :

x = 7

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2 years ago

Read 2 more answers

Does anyone know this? Also, can you explain how you get the answer? cuz I have 10 other questions same as this.

Nezavi [6.7K]

The answer is 36

Multiply each side by 9

9 times for and 9 times n/9

The n/9 will cancel out so you are left with n= 9 times 4

This comes to 36

7 0

2 years ago

I need help with this problem

Kobotan [32]

Step-by-step explanation:

diameter = 3ft

radius = 3/2 ft

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= 4.71 ft

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3 years ago

A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi

viktelen [127]

Answer:

Side length = $\sqrt{\frac{A}{3} }$ cm , Height = $\frac{1}{2} \sqrt{\frac{A}{3} }$ cm , Volume = $\frac{A\sqrt{A}}{6\sqrt{3} }$ cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

$y = \frac{A - x^{2} }{4x}$

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( $\frac{A - x^{2} }{4x}$ )

V = $\frac{Ax - x^{3} }{4}$

To find max volume put V' = 0

So taking derivative equation becomes

$\frac{A - 3 x^{2} }{4} = 0$

A = 3 $x^{2}$

$x^{2}$ = $\frac{A}{3}$

x = $\sqrt{\frac{A}{3\\} }$

put value of x in equation 1

y = $\frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }$

y = $\frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }$

y = $\frac{1}{2} \sqrt{\frac{A}{3} }$

So the volume will be

V = $x^{2}$ × y

Put values of x and y from equation 2 & 3

V = $\frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )$

V = $\frac{A\sqrt{A}}{6\sqrt{3} }$

8 0

3 years ago

What is squre root of 8

IceJOKER [234]

Answer:

2.838

Step-by-step explanation:

put it in the calculator.

6 0

2 years ago