What construction does the image below demonstrate?

1 answer:

8 0

<span>Based on the problems I have recently done on FLVs with this though, is that if you connect the center of the arcs to the top intersection point, if the angle degrees, and opposite arcs are the same then it is an equilateral triangle.</span>

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Express the integral as an iterated integral in six different ways, where E is the solid bounded by y=4-x^2-4z^2 and y=0

zmey [24]

Assuming you need the integral expressing the volume of $E$ , the easiest setup is to integrate with respect to $y$ first.

This is done with either

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dx\,\mathrm dz$
$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dz\,\mathrm dx$

Thanks to symmetry, integrating with respect to either $x$ or $z$ first will be nearly identical.

First, with respect to $x$ :

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dy\,\mathrm dz$
$\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dz\,\mathrm dy$

Next, with respec to $z$ :

$\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$
$\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dx\,\mathrm dy$

5 0

2 years ago

Calculate the upper and lower limit for a 95% confidence interval about this mean. a family needs a new car, but isn't sure they

Ket [755]

<span>Answer: Where:
θ = confidence value
n = number of observations
μ = mean
Θ = standard deviation
... then your interval will be:
μ - θΘ/√n ≤ X ≤ μ - θΘ/√n
For some reason they want you to calculate the standard error, which is the Θ/√n section, and I mentioned the 1.96 value, so the above equation simplifies to: μ - 1.96SE ≤ X ≤ μ - 1.96SE</span>

8 0

3 years ago

Identify the exponential function graphed in the picture.

Goshia [24]

The answer is D i think because the line has an asymptote of x = 2 and it is the only option with + 2 in the equation

8 0

3 years ago

Hey can someone help me?

ddd [48]

Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)

graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.

y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts

graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.

8 0

2 years ago

3/4ths multiplied by x equals 4 7/8ths what is x

alexandr402 [8]

Answer:

x=13/2

Step-by-step explanation:

3/4x=4 7/8

x= 4 7/8 divided by 3/4

x=13/2

check

3/4*13/2=39/8

=4 7/8

7 0

3 years ago