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3 years ago

How to solve 4m+10 -3m+80

Mathematics

2 answers:

GaryK [48]3 years ago

5 0

If these are all part of the same expression then you combine you like terms which would be 4m+-3m and 10+80.

katrin [286]3 years ago

4 0

The answer is 2(2m+5) for 4m+10 & I can't solve the other one, sorry.

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Laurague here is your answer:)

gayaneshka [121]

Got it :)Thank you!!!!!!!

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2 years ago

The image shows a geometric representation of the function f(x) = x2 – 2x – 6 written in standard form. An algebra tile configur

Over [174]

Answer:

$f(x)=(x-1)^2-7$

Step-by-step explanation:

Standard form:

$f(x)=x^2-2x-6$

Vertex form:

$y=(x-h)^2+k$

(h, k) is the vertex

x is the coordinate of the vertex

To find x use the formula:

$x=\frac{-h}{2a}$

$f(x)=x^2-2x-6$

a=1

b=-2

c=-6

Substitute:

$x=\frac{-(-2)}{2(1)}=1$

Substitute x in equation:

$f(x)=1^2-2(1)-6\\f(x)=1-2-6\\f(x)=-7$

h=1

k=-7

Substitute h, and k into the vertex formula:

$f(x)=(x-1)^2-7$

3 0

3 years ago

Read 2 more answers

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REY [17]

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7 0

2 years ago

The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard

arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ $1^s^t$ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have: $\mu=5\ ft$ $\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1$

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒ $2^n^d$ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1$

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒ $3^r^d$ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2$

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒ $4^t^h$ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3$

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0

3 years ago

High school students from grades 9–10 and 11–12 were asked to choose the kind of band to have play at a school dance: rap, rock,

yanalaym [24]

The correct two-way frequency table for the date will look like this:

RAP ROCK COUNTRY TOTAL
Grades 9-10 40 30 55 125
Grades 11-12 60 25 35 120
TOTAL 100 55 90 245

The sum of the row total is equal to the sum of the column total
125 + 120 = 100 + 55 + 90
245 = 245

8 0

2 years ago

Read 2 more answers