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mr Goodwill [35]
3 years ago
6

The diameter of a semicircle is 8 kilometers. What is the semicircle's radius?

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

Answer:

Since, the raduis is twice the diameter, we divide the diameter by 2 which 4. The radius is 4 km.

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I need some guidance and help on this please.
MatroZZZ [7]
The answer is (3,4) since x=3 and when the line is at x=3, it hits y=4. So the answer is (3,4).
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PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( ! <br> ILL GIVE 40 POINTS .
RSB [31]

Answer:

x = 5

Step-by-step explanation:

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3 years ago
Select the correct answer.
olganol [36]

Answer: transportation

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2 years ago
What is the area of each triangle 24 ft 20 ft
arsen [322]

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3 years ago
Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n
Nady [450]

The equation of f(x) = e^{-6x} by maclaurin series is f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}.

The maclaurin series for f(x) is defined by the following formula:

f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}--------------(1)

Where f^{i} is the i - th derivative of the function

If f(x) = e^{-6x}, then the formula of the i - th derivative of the function is:

f^{i} =(-6)^{i} .e^{-6x}----------------------(2)

Then,

f^{i}(0) = (-6)^{i}

Lastly, the equation of the trascendental function by Maclaurin series is: f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i}  }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}---------------(3)

Hence,

The equation of f(x) = e^{-6x} by maclaurin series is f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}.

Find out more information about maclaurin series here

brainly.com/question/24179531

#SPJ4

4 0
1 year ago
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