<h3>
Answer: (x+1)(x+3)</h3>
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Explanation:
Let's assume it factors into (x+a)(x+b)
The goal is to find the two numbers a and b.
FOIL out (x+a)(x+b) to get x^2+(a+b)x+ab
Note how a+b is the middle term and ab is the last term.
In the original expression, 4 is the middle term and 3 is the last term.
So we need to find two numbers that
There are two ways to multiply to 3 and they are
- 1 times 3 = 3
- -1 times -3 = -3
But only the first way has the factors add to 4. So that means a = 1 and b = 3.
Therefore (x+a)(x+b) = (x+1)(x+3)
And x^2+4x+3 = (x+1)(x+3)
You just add all the sides together for perimeter
the answer is105
Answer:
The number of packs are peanuts butter are 4 .
Step-by-step explanation:
As given
Kylee bought a pack of 12 cookies.
one-third if the cookies are peanut butter.
Thus
![Number\ of\ packs\ of\ peanuts\ butter = \frac{1}{3}\times Total\ number\ of\ packs](https://tex.z-dn.net/?f=Number%5C%20of%5C%20packs%5C%20of%5C%20peanuts%5C%20butter%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5Ctimes%20Total%5C%20number%5C%20of%5C%20packs)
![Number\ of\ packs\ of\ peanuts\ butter = \frac{1}{3}\time 12](https://tex.z-dn.net/?f=Number%5C%20of%5C%20packs%5C%20of%5C%20peanuts%5C%20butter%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5Ctime%2012)
![Number\ of\ packs\ of\ peanuts\ butter = \frac{12}{3}](https://tex.z-dn.net/?f=Number%5C%20of%5C%20packs%5C%20of%5C%20peanuts%5C%20butter%20%3D%20%5Cfrac%7B12%7D%7B3%7D)
Number of packs are peanut butter = 4
Therefore the number of packs are peanuts butter are 4 .