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vovangra [49]
3 years ago
5

There are 52 weeks in one year. If cindy drew three pictures each week, for 2 years, how many pictures did cindy draw?

Mathematics
1 answer:
Andrews [41]3 years ago
3 0

Answer:

104 pictures

Step-by-step explanation:

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I can't figure out how to do this problem. Could somebody help me?
Verizon [17]

start by plugging in the value you already have, in this case, 5 for y.

-4x-3(5)=17

-4x-15=17

-4x=32

x=-8

however, since a is a+1, a would be 7 (making x 8)

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8 0
3 years ago
The government of the Republic of Lemon Island plans to transform their lemon-based economy into a tourism-based economy. They d
NNADVOKAT [17]

Step-by-step explanation:

dy/dt = (A − Be^(-t/5)) y

(a) First, find the general solution by separating the variables and integrating.

dy / y = (A − Be^(-t/5)) dt

dy / y = [A + 5B (-⅕ e^(-t/5))] dt

ln |y| = At + 5B e^(-t/5) + C

y = e^(At + 5B e^(-t/5) + C)

y = Ce^(At + 5B e^(-t/5))

Given that A = 0.06, B = 0.04, and y(0) = 50×10⁶ − 10×10⁶ = 40×10⁶:

40×10⁶ = Ce^(0.06(0) + 5(0.04) e^(-0/5))

40×10⁶ = Ce^(0.2)

C = 40×10⁶ e^(-0.2)

y = 40×10⁶ e^(-0.2) e^(0.06t + 0.2 e^(-t/5))

y = 40×10⁶ e^(-0.2 + 0.06t + 0.2 e^(-t/5))

(b) If A = 0.02 and B = 0, and there is no transformation (y(0) = 50×10⁶), then:

50×10⁶ = Ce^(0.02(0) + 0)

50×10⁶ = C

y = 50×10⁶ e^(0.02t)

Comparing to the answer from part (a):

40×10⁶ e^(-0.2 + 0.06t + 0.2 e^(-t/5)) = 50×10⁶ e^(0.02t)

e^(-0.2 + 0.04t + 0.2 e^(-t/5)) = 5/4

-0.2 + 0.04t + 0.2 e^(-t/5) = ln(5/4)

-5 + t + 5e^(-t/5) = 25 ln(5/4)

t + 5e^(-t/5) = 5 + 25 ln(5/4)

Solve with a calculator:

t = 9.886

The transformed economy surpasses the untransformed economy in the 10th year.

(c) In year t=5, the size of the transformed economy is:

y = 40×10⁶ e^(-0.2 + 0.06(5) + 0.2 e^(-5/5))

y = 47.6×10⁶

The percent growth is:

(47.6×10⁶ − 40×10⁶) / 40×10⁶ × 100% = 19%

The growth rate is greater than 4%, so the current government can expect to be reelected.

3 0
3 years ago
Jhon can solve 6 math problems in 20 minutes while another student, Juaqine, can solve the same 6 math problems at a rate of 1 p
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Answer:

  Jhon

Step-by-step explanation:

At the rate of 4 minutes per problem, it take Juaqine ...

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to solve the problems.

That is more time than it takes Jhon, so Jhon is faster.

3 0
3 years ago
Find an angle in the normal range(0 degrees to 360 degrees, or 0 to 2pi radians) whose terminal side points in the same directio
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Answer:

d) 9pi/8

Step-by-step explanation:

25pi/8 - 2pi

(25-16)pi/8

9pi/8

3 0
3 years ago
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kotegsom [21]

Answer:

k = +10 or -10

Step-by-step explanation:

It's given in the question that the roots of the eqn. are real and equal. So , the discriminant of the eqn. should be equal to 0.

=  >  {b}^{2}  - 4ac = 0

=  >  {( - 2k)}^{2}  - 4 \times 5 \times 20 = 0

=  > 4 {k}^{2}  - 400 = 0

=  > 4( {k}^{2}  - 100) = 0

=  >  {k}^{2}  - 100 = 0

=  > k =  \sqrt{100}  =  + 10 \: or \:  - 10

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3 years ago
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