N2H4
<span>Each nitrogen weighs 14.01 and each H weighs 1.01. !4.01+14.01+1.01+1.01 = 32.06 (roughly) </span>
Answer:
V = 27.98 L
Explanation:
Given data:
Mass of CO₂ = 33.0 g
Pressure = 500 torr
Temperature = 27°C
Volume occupied = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 33.0 g/ 44 g/mol
Number of moles = 0.75 mol
Volume of CO₂:
PV = nRT
R = general gas constant = 0.0821 atm.L/ mol.K
Now we will convert the temperature.
27+273 = 300 K
Pressure = 500 /760 = 0.66 atm
By putting values,
0.66 atm×V = 0.75 mol × 0.0821 atm.L/ mol.K × 300 K
V = 18.47 atm.L/0.66 atm
V = 27.98 L
Answer: The mass of 405 ml of cresol is 415 grams
Explanation:
Density is defined as the mass contained per unit volume.
Given : Density of cresol = 1024 g/L
Volume of cresol = 405 ml = 0.405 L ( 1L=1000ml)
Putting in the values we get:
Thus mass of 405 ml of cresol is 415 grams
Answer:
See explanation below
Explanation:
In this case, we can use the Boyle's law. Assuming that the temperature of both trial remains constant, then:
P₁V₁ = P₂V₂ (1)
You should note that this expression is usable when you are dealing with gases. However, we can treat this unknown liquid as a gas, because all the air on the flask is removed, and we can assume that the liquid can behave like an ideal gas.
So using the above expression, we can solve for P₂:
P₂ = P₁V₁ / V₂ (2)
In this case, we already have the values of presures and volume, so replacing in this expression:
P₂ = 34.5 * 5 / 214
<h2>
P₂ = 0.806 kPa</h2>
This should be the pressure of the liquid.
Hope this helps
