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3 years ago

Salicylic acid (C4H603) reacts with acetic anhydride (C«H603) to form acetylsalicylic acid (C9H30.).

Chemistry

1 answer:

Vinvika [58]3 years ago

5 0

The limiting reactant is salicylic acid (C₇H₆O₃).

Explanation:

We have the following chemical reaction where salicylic acid (C₇H₆O₃) reacts with acetic anhydride (C₄H₆O₃) to form acetylsalicylic acid (C₉H₈O₄) and acetic acid (C₂H₄O₂):

C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + C₂H₄O₂

We have started with 70.0 g of salicylic acid (C₇H₆O₃) and 80.0 g acetic anhydride (C₄H₆O₃).

First we calculate the number of moles of each reactant:

number of moles = mass / molar weight

number of moles of salicylic acid = 70 / 138 = 0.507 moles

number of moles of acetic anhydride = 80 / 102 = 0.784 moles

We see from the chemical reaction that 1 mole of acetic anhydride (C₄H₆O₃) reacts with 1 mole of salicylic acid (C₇H₆O₃) so 0.784 moles of acetic anhydride (C₄H₆O₃) will react with 0.784 mole of salicylic acid (C₇H₆O₃) but we only have 0.507 moles of salicylic acid (C₇H₆O₃). The limiting reactant is salicylic acid (C₇H₆O₃).

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limiting reactant

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