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murzikaleks [220]
3 years ago
9

The temperature of a sample of water increases from 30.0 degrees C to 40.0 degrees C as 6540 joules of heat are added. What is t

he mass of the sample of water?
Chemistry
2 answers:
k0ka [10]3 years ago
4 0

Answer:

166 g

Explanation:

The equation of specific heat capacity is:

ΔE = mcΔtheta

ΔE = 6540J

c = 4200J/kg°C

Δtheta = 40 - 30 = 10

6540 = m × 4200 × 10

6540 = m × 42000

6540 ÷ 42000 = m

m = 0.15571428...

m = 0.166 kg

m = 166 g

Leviafan [203]3 years ago
3 0

Answer:  166 g

Explanation: q = mC∆T

q = heat = 6940 J

m = mass = ?

C = specific heat of water = 4.184 J/g/deg

∆T = change in temperature = 40.0 - 30.0 = 10.0ºC

6940 J = (m)(4.184J/g/deg)(10 deg)

m = 165.9 g = 166 g

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Suppose a solution is described as concentrated. Which of the following statements can be concluded? Select the correct answer b
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  • last option: none of<u> the above.</u>

Explanation:

Describing a solution as<em> concentrated</em> tells that the solution has a relative large concentration, but it is a qualitative description, not a quantitative one, so this does not tell really how concentrated the solution is. This is, the term concentrated is a kind of vague; it just lets you know that the solution is not very diluted, but, as said initially, that there is a relative large amount (concentration) of solute.

One conclusion, of course, is that <u>the solute is soluble</u>: else the solution were not concentrated.

On the other hand, the terms saturated and <em>supersaturated</em> to define a solution are specific.

A saturated solution has all the solute that certain amount of solvent can contain, at a given temperature. A <u>supersaturated solution has more solute dissolved than the saturated solution</u> at the same temperature; superstaturation is a very unstable condition.

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5 0
3 years ago
What is the barometric pressure exerted in pascals (Pa) of a column of decane (density = 0.7300 g/cm3) 636.2 mm in height?
BartSMP [9]
<h3>Answer:</h3>

4551.37 Pascals

<h3>Explanation:</h3>

The pressure refers to the force exerted by a substance per unit area.

The pressure is liquid is calculated by;

P = height × density × gravitational acceleration

In this case;

Height = 636.2 mm

Density = 0.7300 g/cm³

g = 9.8 N/kg

We need to convert mm to m and g/cm³ to kg/m³

Therefore;

Height = 636.2 mm ÷1000

           = 0.6362 m

Density = 0.73 g/cm³ × 1000 kg/m³

             = 730 kg/m³

Then, we can calculate the pressure;

Pressure = 0.6362 m × 730 kg/m³ × 9.8 N/kg

              = 4551.3748 pascals

               = 4551.37 Pascals

Therefore, the pressure of the column of decane is 4551.37 Pascals

5 0
3 years ago
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