The decomposition time : 7.69 min ≈ 7.7 min
<h3>Further explanation</h3>
Given
rate constant : 0.029/min
a concentration of 0.050 mol L to a concentration of 0.040 mol L
Required
the decomposition time
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time
For first-order reaction :
[A]=[Ao]e^(-kt)
or
ln[A]=-kt+ln(A0)
Input the value :
ln(0.040)=-(0.029)t+ln(0.050)
-3.219 = -0.029t -2.996
-0.223 =-0.029t
t=7.69 minutes
I think that it is D because the higher the molecular mass, the higher it's boiling point. I hope that helped:) Bye!
A granite catches fire more quickly
Answer: Option B. 76.83L
Explanation:
1 mole of a gas occupy 22.4L at stp. This implies that 1mole of Radon also occupy 22.4L at stp.
If 1 mole of Radon = 22.4L
Therefore, 3.43 moles of Radon = 3.43 x 22.4 = 76.83L
The IUPAC name for the given product is 2 chloro Butane.
<h3>What is IUPAC nomenclature?</h3>
IUPAC stands for 'International Union of Pure and Applied Chemistry', which givers some rule for designing the name of compounds of chemistry.
- In the given product total four carbon atoms are present and between all of them single bonds are present.
- In the second carbon atom, chlorine group is present.
- During the nomenclature process, first we write down the name of the attached group which is followed by the alkane chain.
Hence name of the product is 2 chloro Butane.
To know more about IUPAC nomenclature, visit the below link:
brainly.com/question/26635784
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