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3 years ago

PLEASE HELP WORTH 15 PTS!!!!1

Mathematics

2 answers:

IRINA_888 [86]3 years ago

7 0

Its the 3rd answer dfsadfafdafdfasdfsdfsdfsdfdfsddfds

zimovet [89]3 years ago

6 0

It looks like the terms are:
(7x2 + 5) and (x - 3)

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Using (x + a) (x + b) = x² + (a + b) x + ab, evaluate 75 x 77

Gre4nikov [31]

(x + a) (x + b) = x² + (a + b) x + ab

75 * 77=

=(70+5)(70+7)

=70²+(5+7)*70+5*7

=4900+12*70+35

=4900+840+35

=5775

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3 years ago

What is mean in math

PSYCHO15rus [73]

The mean is the average of the numbers. to find the mean add up the numbers and divide by how many numbers there are

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3 years ago

Paul spelled 6 out of 16 words correctly on his spelling test. What fraction of the words did he misspell?

olya-2409 [2.1K]

Answer:

5/8 are spelled incorrectly

Step-by-step explanation:

There are 16 words

He spelled 6 correctly

That means he spelled 16-6 = 10 incorrectly

The fraction spelled incorrectly is wrong/total

10/16

Simplify by dividing the top and bottom by 2

5/8

5 0

3 years ago

Read 2 more answers

What is the solution of

kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

$(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}$

Simplifying on the left side, and applying on the right side the formula:

$(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}$

$2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x$

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

$(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x$

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

$x^{2}-16x=16x-16x\\ x^{2}-16x=0$

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2$

x=0 is a solution

2) x=16

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2$

x=16 is a solution

Then the solutions are x=0 and x=16

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3 years ago

How many pairs of parallel sides does a trapezoid have? none/ one/ three/ two

telo118 [61]

A trapezoid has two parallel sides, but the top one is shorter than the bottom one

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3 years ago