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MaRussiya [10]
3 years ago
15

Ethene is the first member of the

Chemistry
1 answer:
DanielleElmas [232]3 years ago
5 0
It will be:

b. Alkyne* series

* You have done a spelling mistake here. It will be "Alkene" not  "Alkyne".
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A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezing point depression of
sergij07 [2.7K]
From the equation; ΔTf = Kf × m
Where, Kf for water = 1.853 K kg/mole; m is the molarity = number of solute/amount of solvent in kg.
Glucose is the solute whose molecular mass is 180 g/mole and water is the solvent. 
Moles of solute = 15.5/180 = 0.0861 moles
Amount of solvent in kg = 245/1000 = 0.245 Kg
Therefore; molarity = 0.0861/0.245 = 0.3515 moles/Kg
Therefore; ΔTf = 1.853 × 0.3515 = 0.6513 K
Hence; the depression in freezing point is 0.6513 
The freezing point of solution will therefore be;
= 273 - 0.6513 = 272.3487 K

7 0
3 years ago
A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
sertanlavr [38]

Answer: The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.947 atm

P_2 = final pressure of gas = 0.987 atm

V_1 = initial volume of gas = 150 ml

V_2 = final volume of gas = 144 ml    

T_1 = initial temperature of gas = 25^0C=(25+273.15)K=298.15K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}

T_2=298.31K=(298.31-273.15)^0C=25.16^0C

The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

4 0
3 years ago
(Pls help i will give brainlyest) Label the missing parts of the diagram.
WARRIOR [948]

Answer:

                                 Sedimentary rock

Metamorphic rock                                 Igneous rock

4 0
3 years ago
When reptiles and fish young are they look like __ similar to their parents? Please hurry!!
WARRIOR [948]
Fishes yes according to the age, reptiles yes
8 0
3 years ago
Determine the mass in grams of Avogadro's number of C12H22O11
Allushta [10]

Answer:

2.059524x10^26 if im not wrong

Explanation:

avogadro's number is 6.022x10^23

5 0
3 years ago
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