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Sunny_sXe [5.5K]
3 years ago
13

sulfur trioxide is used in many products from explosive to glue. which two criteria are most important in engineering a process

to produce this compound?​
Chemistry
2 answers:
olga55 [171]3 years ago
7 0

Answer:

"the process must be safe for people and the environment."  "the process should produce a high volume of product from the input reactants."

Explanation:

andrew-mc [135]3 years ago
3 0

Answer: The process should produce a high volume of product from the input reactants. The process must also be safe for people and the enviorment. - Ape x

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What do we call the stars whose properties follow the patterns?
muminat

Answer:

It is called Asterism.

Explanation:

It is Asterism because Asterism refers to a pattern of stars that are seen in night sky and are very distinctive and identifiable. These group of starts have patterns. It visually seen collection of stars and it's indicate their properties and the lines that connect the stars together. It actually range from small shapes of stars to more complex stars that cover segment of the sky. The stars may be bright naked or have similar brightness.

4 0
3 years ago
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
Ede4ka [16]

<u>Answer:</u> The mass of glucose in final solution is 1.085 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}      ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated glucose solution

M_2\text{ and }V_2 are the molarity and volume of diluted glucose solution

We are given:

M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL

Putting values in above equation, we get:

0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g

Hence, the mass of glucose in final solution is 1.085 grams

4 0
3 years ago
The reaction 2PH3(g)+As2(g)⇌2AsH3(g)+P2(g) has Kp=2.9×10−5 at 873 K. At the same temperature, what is Kp for each of the followi
slavikrds [6]

Answer:

Part A

Kp = 3.4 x 10⁴

Part B

Kp = 2.4 x 10⁻¹⁴

Part C

Kp = 1.2 x 10⁹

Explanation:

2PH₃(g) + As₂(g)  ⇌ 2 AsH₃(g) + P₂(g)  Kp = 2.9 x 10⁻⁵

Kp = [AsH₃]²[P₂]/[PH₃]²[As]  = 2.9 x 10⁻⁵

Part A

it is the inverse of the equilibrium given

Kp(A) = 1/ Kp = 1 / 2.9 x 10⁻⁵ = 3.4 x 10⁴

Part B

Is the equilibrium where the coefficients have been multiplied by 3,

Kp(B) = ( Kp )³ = ( 2.9 x 10⁻⁵ )³ = 2.4 x 10⁻¹⁴

Part C

This is the  reverse equilibrium multipled by 2.

Kp(C) = ( 1/Kp)² = ( 1/ 2.9 x 10⁻⁵ )² = 1.2 x 10⁹

8 0
3 years ago
A liquid has a density of 4.0 oz/cup. Express the density of the liquid in lb/gallon.
Julli [10]

Answer:

3.99998575239 pounds per gallon (US)

7 0
2 years ago
When converting from moles to molecules OR molecules to moles you use what quantitative value?
miv72 [106K]
24 because it amen r amend
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3 years ago
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