Combustion of <span>acetylene :
</span><span>molar ma</span>ss acetylene ( C₂H₂ ) = 26.0 g/mol and CO₂ = 44.0 g/mol
<span>
2 C₂H₂ + 5 O₂ ---> 4 CO₂ + 2 H₂O
</span>
2 moles C₂H₂ --------> 4 moles CO₂
? moles C₂H₂ --------> 1.10 moles CO₂
moles C₂H₂ = 1.10 * 2 / 4
moles C₂H₂ = 0.55 moles of C₂H₂
Mass acetylene:
m = n * mm
m = 0.55 * 26.0
m = 14.3 g
hope this helps!
So the GFM of O2 is 32.00g/mol
If we have 1 mole of O2 we have 32.00g
32.00g/22.4L = 1.42857… aprox. 1.43g/L
Sorrr I’m not quite sure where PV=nRT comes in
<span>
<span> 250g H2SO4 x 1moleH2SO4/ 98g mole H2SO4 x 4moles Oxygen/1moleH2SO4 x 1moleOxgen/16g Oxygen
= 163.27g Oxygen
my figures aren't exact....so it's 160g </span>
</span>
Answer: 22.3 *10^23 S atoms
Explanation:
Protists belong to the group eukaryotes (having their DNA enclosed
inside the nucleus). They are not plants, nimals or fungi but they act like
one. They can be in general subgroups such as unicellular algae, protozoa and
molds. They thrive in environments with little sunlight. The answer is
letter B.