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Dovator [93]
3 years ago
5

Heres ANOTHER question last one of the day

Mathematics
1 answer:
Ugo [173]3 years ago
8 0

Answer:

ihhhhhhhsjajskjsjziaja

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Which graph shows the equation c = 10+ 3t, where c is the total cost of going to the carnival and t is the number of $3 tickets
lubasha [3.4K]

we have

c = 10+ 3t

where

c---------> is the total cost of going to the carnival

t---------> is the number of \$3 tickets purchased

we know that

<u>the domain of the function is the interva</u>l---------------> [0,∞)

Because the number of tickets can not be negative

<u>The range of the function is the interval</u>-------------> [10,∞)

Because the total cost can not be negative

using a graph tool

see the attached figure

The answer in the attached figure

7 0
3 years ago
Read 2 more answers
The sum of the measures of the angles of a triangle is 180°. The middle-sized angle measures 3° more than 2 times the smallest a
Anit [1.1K]

Answer:

13° , 29° , 138°

Step-by-step explanation:

let x be the smallest angle , then

2x + 3 is the middle angle and

2x + 3 + 109 is the largest angle

summing the 3 angles and equating to 180

x + 2x + 3 + 2x + 3 + 109 = 180 , that is

5x + 115 = 180 ( subtract 115 from 180 )

5x = 65 ( divide both sides by 5

x = 13

2x + 3 = 2(13) + 3 = 26 + 3 = 29

2x + 3 + 109 = 29 + 109 = 138

the 3 angles are 13° , 29° , 138°

6 0
1 year ago
Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

  • f(a) = a c {1} if a has an odd number of 1's
  • f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

  • If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

3 0
3 years ago
Curtis spent $60 less than 3 times what Jaclyn spent. Curtis spent $36. How much did Jaclyn spend?
Rainbow [258]

Answer:

hsjsjjjsijsjbduejwns

5 0
2 years ago
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Put the following equation of a line into slope-intercept form 4x+3y=-21
s2008m [1.1K]

Answer: Y=(\frac{4}{3}) x-7

Step-by-step explanation:

8 0
3 years ago
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