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2 years ago

78.5 g of Carbon dioxide gas fills a container that is 1.2 L. What is the

1 answer:

7 0

Given the mass of the gas, temperature and volume of the cylinder, the pressure of the Carbon dioxide gas is 38.7atm.

<h3>What is Ideal Gas Law?</h3>

The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.

It is expressed as;

PV = nRT

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )

Given that;

Mass of Carbon dioxide = 78.5g

Molar mass of Carbon dioxide 44.01 g/mol
Amount of gas n = 78.5g ÷ 44.01 g/mol = 1.78mol
Volume L = 1.2L
Temperature T = 45.1°C = 318.25K
Pressure P = ?

PV = nRT

P = nRT / V

P = ( 1.78mol × 0.08206 Latm/molK × 318.25K ) / 1.2L

P = 46.4857591Latm / 1.2L

P = 38.7atm

Therefore, given the mass of the gas, temperature and volume of the cylinder, the pressure of the Carbon dioxide gas is 38.7atm.

Learn more about Ideal Gas Law here: brainly.com/question/4147359

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For a molecule of hydrazoic acid (HN3, also known as hydrogen azide), the atoms are arranged as HNNN. One resonance form of HN3

disa [49]

Answer:

0; +1; -1

Explanation:

The resonance structure of HN₃ is shown below (you can also use horizontal dashes to represent the bonding pairs).

The molecule has 16 valence electrons, and each N atom has an octet.

To get the formal charges, cut the covalent bonds in half.

Each atom gets the electrons on its side of the cut.

Formal charge = valence electrons in isolated atom - electrons on bonded atom

FC = VE - BE

(a) On Nₐ

VE = 5

BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5

FC = 5 - 5 = 0.

(b) On Nb:

VE = 5

BE = 4 bonding electrons = 4

FC = 5 - 4 = +1

(c) On Nc:

VE = 6

BE = 2 lone pairs(4) + 2 bonding electrons = 4 + 2 = 6

FC = 5 - 6 = -1

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3 years ago

The diagram shows Niels Bohr’s model of an atom.

PtichkaEL [24]

Answer:

Energy is absorbed, and an emission line is produced.

Explanation:

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3 years ago

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What is the oh- in a solution with a poh of 5.71

Rudik [331]

Answer:- The hydroxide ion concentration of the solution is $1.95*10^-^6$ .

Solution:- The formula used to calculate pOH from hydroxide ion is:

$pOH=-log[OH^-]$

When pOH is given and we are asked to calculate hydroxide ion concentration then we multiply both sides by negative sign and take antilog and what we get on doing this is:

$[OH^-]=10^-^p^O^H$