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Leno4ka [110]
2 years ago
5

78.5 g of Carbon dioxide gas fills a container that is 1.2 L. What is the

Chemistry
1 answer:
Daniel [21]2 years ago
7 0

Given the mass of the gas, temperature and volume of the cylinder, the pressure of the Carbon dioxide gas is 38.7atm.

<h3>What is Ideal Gas Law?</h3>

The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.

It is expressed as;

PV = nRT

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )

Given that;

  • Mass of Carbon dioxide = 78.5g
  • Molar mass of Carbon dioxide 44.01 g/mol
  • Amount of gas n = 78.5g ÷ 44.01 g/mol = 1.78mol
  • Volume L = 1.2L
  • Temperature T = 45.1°C = 318.25K
  • Pressure P = ?

PV = nRT

P = nRT / V

P = ( 1.78mol × 0.08206 Latm/molK × 318.25K ) /  1.2L

P = 46.4857591Latm / 1.2L

P = 38.7atm

Therefore, given the mass of the gas, temperature and volume of the cylinder, the pressure of the Carbon dioxide gas is 38.7atm.

Learn more about Ideal Gas Law here: brainly.com/question/4147359

#SPJ1

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Calculate the number of atoms in 112 g of iron.​
mr_godi [17]

Answer:

1 mole of iron (Fe) = 56 g (molar mass)

Since 56 g of iron = 1 mol.

Therefore, 112 g of iron= 1/ 56 ×112 mol = 2 mol.

Explanation:

8 0
3 years ago
you are holding a bowling ball with a mass of 6 kg at a height of 1 meter. How much gravitational potential energy does the bowl
Bumek [7]

The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,

PE=mgh

PE=(6 kg)(9.8 m/s^2)(1 m)

PE=58.8 kg•m^2/s^2 or 58.8 Newtons

The GPE of the bowling ball under these conditions would be about 59 Newtons.

Hope this helps!

7 0
3 years ago
67.4 L of sulfur dioxide (SO2) gas at 0.0C and at 1 atm of pressure is equivalent aren’t to how many moles?
gizmo_the_mogwai [7]

Solution here,

Volume(V)=67.4 L

Pressure(P)=1 atm

Temperature(T)=(0+273)K=273K

Universal gas constant(R)=0.0821 L.atm.mol^-1K^-1

No. of moles(n)=?

Now,

PV=nRT

or, 1×67.4=n×0.0821×273

or, 67.4=22.4n

or, n=67.4/22.4

or, n=3

therefore, required no. of mole is 3.

6 0
3 years ago
Using the balanced equation below, how many moles of water can be produced when 4 grams of Hydrogen react? 2H2(g)+O2(g) —&gt; 2H
gavmur [86]

Answer:

4 × 10 g

Explanation:

Step 1: Write the balanced equation

2 H₂(g) + O₂(g) ⇒ 2 H₂O(I)

Step 2: Calculate the moles corresponding to 4 g of H₂

The molar mass of H₂ is 2.02 g/mol.

4 g × 1 mol/2.02 g = 2 mol

Step 3: Calculate the moles of H₂O produced from 2 moles of H₂

The molar ratio of H₂ to H₂O is 2:2. The moles of H₂O produced are 2/2 × 2 mol = 2 mol.

Step 4: Calculate the mass corresponding to 2 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

2 mol × 18.02 g/mol = 4 × 10 g

7 0
2 years ago
Can someone help me please? I’d appreciate it! Also please do not send me a link or delete your answer! Thanks
chubhunter [2.5K]

Answer:

14.53ML

Explanation:

V1=218

V2=?

P2=15p1

USING BOYLE'S LAW

P1V1=P2V2

V2=P1V1/P2=P1(218ML)/15P1

=14.53ML

5 0
3 years ago
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