All categories

1 year ago

What is the approximate power per area emitted by the inside wall of an oven when baking a cake in w/m2?

Chemistry

1 answer:

serious [3.7K]1 year ago

5 0

The approximate power per area emitted by the inside wall of an oven when baking a cake in w/m2 is 6 x 3^4.

<h3 /><h3>What is power per area?</h3>

Comparing the surface power density of various industrial energy sources is crucial. Geographer Vaclav Smil popularised the idea. In the pertinent literature, the phrase is sometimes abbreviated to "power density," which may cause confusion with similar or homonymous concepts.

The power obtained per square metre of Earth's surface area utilised by a particular energy system, including all supporting infrastructure, manufacturing, fuel mining (if relevant), and decommissioning, is expressed in W/m2. Due to the high power density of fossil fuels and nuclear energy, substantial amounts of electricity may be produced in very small spaces at power plants.

6 x 3^4 (for reference Humans are about 300 K)

to learn more about surface power density go to -

brainly.com/question/20038729

#SPJ4

You might be interested in

A 10.0 g sample of an unknown liquid is vaporized at 120.0°C and 5.0 atm. The volume of the vapour is found to be 568.0 mL. The

Minchanka [31]

Answer:

molecular formula of liquid = C₈H₁₈

Explanation:

First we determine the empirical formula of the liquid:

Number of moles of each element present in the liquid = % mass / molar mass

For Carbon, (molar mass = 12.01 g/mol) : 84.2/12.01 =7.011 moles

For Hydrogen (molar mass = 1.01 g/mol) : 15.8/1.01 = 15.643

Simplest mole ratio of the elements, C : H is given by:

C = 7.011/7.011 = 1.0

H = 15.643/7.011 = 2.23

Multiplying through with 5, C:H = 5:11

Therefore, empirical formula is C₅H₁₁

The molecular mass of the liquid is next determined:

Using PV = nRT to find the number of moles of the liquid present

P = 5.0 atm; V = 568.0 mL = 0.568 L; R = 0.082 L*atmmol⁻¹ K⁻¹; T = 273 + 120 = 393 K

n = PV/RT = (5*0.568)/0.082*393

n = 0.088 moles

Molar mass of liquid = mass/no of moles = 10.0 g/ 0.088 moles = 113.63 gmol⁻¹

Molecular formula = n(empirical formula)

Molar mass of empirical formula, C₅H₁₁ = 71 gmol⁻¹

n = molecular mass/empirical mass = 113.63/71 = 1.6

Therefore, molecular formula = 1.6*(C₅H₁₁) = C₈H₁₈

6 0

3 years ago

HELP ASAP!!

Ksju [112]

109/8.56=12.7
50+12.7
V=62.7

Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer

4 0

3 years ago

Read 2 more answers

What is name of the towering volcanoes that form from both lava flows and cinder rocks?

MatroZZZ [7]

The answer is B hope it helps

4 0

3 years ago

Read 2 more answers

Movement of electrons about a central nucleus is a concept by whom?

Alenkasestr [34]

The answer is bohr hope this helps :)

5 0

3 years ago

Read 2 more answers

What type of central-atom orbital hybridization corresponds to each electron-group arrangement:

galina1969 [7]

Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized $sp^3$ orbitals → $sp^3$ hybridization.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about Hybridization

brainly.com/question/22765530

#SPJ4

3 0

1 year ago